GoConqr has a new look! Let us know what you think.

Notes

Dot Product

Deleted user User has deleted their subject information English 3 pages

Content of the notes (3)

Page 1

The Dot Product

A type of vector multiplication.

The vectors a and b must be of the same dimensions.

The dot product gives a scalar number.

Example: Find the dot product of <6,-2,0> and <5,1,4>.

Apply the dot product formula (next page) :

= 6*5+-2*1+0*4 = 30-2 = 28 (scalar)

Example: Find the angle between <5,-1,2,-3> and <0,6,-2,-3>.

Note that these two are the same dimension, n=4.

First find a dot b, then find the magnitudes |a| and |b|.

a dot b = 5*0+(-1)*6+2*(-2)+(-3)*(-3) = +6-4+9 = -1

|a| = sqrt(5^2+1^2+2^2+3^2) = sqrt(39)

|b| = sqrt(0^2+6^2+2^2+3^2) = sqrt(49) = 7

Apply the angle formula for dot product (next page):

-1=7sqrt(39)cos(theta), cos(theta)=-1/(7sqrt(39)), theta=cos^-1(-1/7sqrt(39))

= 1.5937 rad

Example: Find the acute angles at an intersection of two functions, a parabola and line.

Steps:

First find where the two functions intersect. Set the two equal to each other.

Simplify, set equal to 0.

Find values of x by factoring.

Plug in these values of x into the parabola equation to find the corresponding values of y.

Find the derivative of parabola, y'. Plug in the values of x found earlier. These give the slopes of the functions at x1, x2...

Find the tangent vectors for each function:

For a line: take the slope of the line from the line function. ex. for a slope of three, the tangent vector is <1,3> (1 unit over, 3 units up)

For a parabola: need tangent vectors at both points of intersection.

Find the value of y' for each x (plug in the found x values into the derivative of the parabola)

For each, this is the slope.

Turn the slope into a tangent vector like the example for a line.

From here, find the angles between the tangent vectors, using the theta dot product formula (next page).

Page 2

Equations

a dot b = scalar

a dot b = |a||b|*cos(theta)

|a| = sqrt(a1^2+a2^2...)

vector of AB =

Comp_a(b)=|b|cos(theta)

Comp_a(b)= ((a dot b) / |a|)

Proj_a(b) = 1/|a|*(comp_a(b)a = ((a dot b)/(|a|^2))a

(Take a, shrink it by 1 over a magnitude, then stretch by a factor of comp_a(b)

Page 3

Properties

Commutativity: a dot b = b dot a

Distributivity: (a+b) dot c = a dot c + b dot c

Norm: a dot a = |a|^2

When a dot b = 0, the angle between the two is 90 degrees.

Information

Description
User has deleted their subject information Note on Dot Product, created by Deleted user on 20/12/2018.
Created by
Deleted user · Dec 2018
Updated
Dec 20, 2018
Views
41
History
  • Created by Darren Hunt · Dec 20, 2018
  • Copied by Darren Hunt · Dec 20, 2018
Rating

Feedback

What is it about?

What do you think of the new look?

How do you like it?