Mapa mental
HYPERBOLIC FUNCTIONS

Contenido del mapa
HYPERBOLIC FUNCTIONS
- defined in terms of exponential functions. comes from complex number expressed in e^(i∮)
SIX HYPERBOLIC FUNCTION
- sinh(spell:shine) =1/2(e^x -e^-x) cosh(cosh)=1/2(e^x-e^-x) tanh(tanch)=(e^2x -1)/(e^2x +1) csch(cosheck)=2/(e^x -e^-x) sech(sheck)=2/(e^x +e^-x) coth(coth)=(e^2x +1)/(e^2x -1)
- GRAPHS
- deduced by looking at e^x and sketch
- Identities
- i apperciate my exsitence from Moon and back = =
- Oborn's rule
- 1. firstly, if we assume that sinx corresponds to sinhx, cosx to coshx ... 2. Oborn's rule states that when you meet a product of sinx in application of their corresponding identities, change the sign. e.g. (sinx)^2 + (cosx)^2 = 1→ -(sinhx)^2 + (cosh)^2 =1
- ABOUT 1
- tanh^2 +sech^2 =1 coth^2 -csch^2 =1 cosh^2 -sinh^2 =1
- 2倍角
- e.g. csch2x= 1/(sinh2x)= 1/(2sinxcosx)
INVERSE HYPERBOLIC FUNCTION
- sin^-1 OR arcsinx =y -->siny =x sin(arcsinx) =x
- GRAPHS
- 1.the graph is the reflection of hyperbolic functions about y =x 2. it must be 1-1 function(mapping), so domain limited
- EXPRESSED IN Log(Ln)
- IHF -->HF -->(By definition) expressed in e^x form --> quadratic function of e^x ---> mapping decided by x=ln(...) ---> domain decided by graph eg. arcsinx =y, siny =x =1/2(e^x -e^-x) -->...
DIFFERENTIATION
- rate of change(看图说话) dy/dx>0 -->positive derivate dy/dx<0 -->negative derivate
- 工具
- 2nd-order derivative (higer-order derivatives)
- FS: ???
- FOR Composite functions
- Quotient rule
- Product rule
- Chain rule
- nx OR x^n please be aware of the constant change.
- e.g. d/dx(arctanhx) --> x^2--(tanhx)^2, (tanhx)'=(sechx)^2 -->...
- d/dx( six HF )
- expressed in e^x form then deriviate it...
- d/dx( six arcHF )
- 1.arcsinx=y--> siny=x (use sub) 2.dy/dx=1/(dx/dy) 3.indentities: about 1--> to convert y-->x
- e.g. d/dx(arcsinhx)=√(1+x^2)--> arcsinhx=y, sinhy=x, dx/dy(sinhy)=dx/dy, coshy=dx/dy--> dy/dx=1/coshy= 1/√(1+sinhy^2) = 1/√(x^2+1)
INTEGRATION
- if y=∫f(x)dx, dy/dx=f(x)
- 工具 (泛)
- TWO DERIVED FORMULAS
- ∫f'(x) /f(x) =ln f(x) +c ∫f(x)^n *f'(x) =f(x)^(n+1)/(n+1) +c --> reverse of product rule
- e.g. ∫tanhx dx & ∫cothx dx --> derived formulas
- trick for ∫tanhx dx *
- BY PARTS *
- when ∫(u)(dv/dx) dx OR ∫(u)(1) dx is harder than ∫(du/dx)(v) dx -->it change GUESS WORK from u(dv/dx) to v(du/dx) -->(现象) 处理 ∫(高次) dx
- to integrate HF & arcHF & lnx, we use integration by parts with v'=1.
- REDUCTION FORMULAS for ∫(f(x))^g(n) * (linear function)^power dx
- find a reduction formula= generate a recurrance sequence. i.e. an intergral In is expressed recurrisively. So as long as we know how to calculate Im for some m, this will work.
- recurrance relation *
- make your life easier= = when calculate I3 OR I4... 注意 domain of n changes.(recurrance relation & In=... differes.) founded by use intergarte by parts several times.> similar to the recurrance relation of number(xn+1=xn + A...)
- 易错点: [...]limits 和 变形后应第一反应带入I(n) other than guess relation
- 在inte 公式的第一步就做变形.就是变形成 ∫u v' dx, (v: linear function) 对于[类似的v]为quadratic function, 变形组合linear function 相乘-->既可以一步integer 的式子*
- many reduction formula need a fiddle... while excusefucking me?
- integrate by parts *2 OR change integrating agent then integrate by part *1 to figure out
- then many reduction formulas need a fiddle like this: '加减改变项目' e.g. (1-x^2)^3/2=(1-x^2)*(1-x^2)^1/2
- u: reducing agent for which has high power
- v': integrating agent for which can be integrate easily
- e.g. ∫arctanhx ... *
- FS + DERIVED FORMULAS
- ∫1/(x^2+C)^n dx= arcHF +c... *
- for every x--> f(x) =Ax +B(拿出A) 每一个x的位置,都能换成f(x). * 需要注意, A 需要 reverse. * 需要注意, 我们关注的是 [被替换的x] 这一项, 而非改变该式子的其他 [未被替换项].
- ∫(分子)/(分母) dx: 分子是分母的崎次变化的那种 ??
- e.g. ∫2e^x/(9+e^2x) dx= 2/3 arctan (e^x/3) *
- ∫1/(x^2+C)^n dx= arcHF +c... *
- PARTIAL FRACTIONS *
- e.g. ∫1/(1-x^2) dx= 1/2∫ 1/(1-x) + 1/(1+x) dx= 1/2ln[(1+x)/(1-x)] + c--> arctanhx
- RECOGNISE A STANDARD FUNCTION : REVERSE WORK
- USING FORMULAS TO CHANGE INTEGRAND
- EXPRESSED IN e^x FORM
- when ∫ e^x dx is easier than ∫...
- e.g. ∫sinhx dx, ∫coshx dx
- Identities
- EXPRESSED IN e^x FORM
- STANDARD SUBSTITUTIONS ??
- use FS for inspiration. every x--> f(x)=Ax+B, 拿出A??
- 2. change integrand, by identities ...
- 1. change respect
- 3. change limit boundaries
- TWO DERIVED FORMULAS
- APPLICATION
- Area of a surface of revolution, A=∫ 2πy ds--> (ds/dx) dx while ds/dx=√(1+(dy/dx)^2) OR (ds/dt) dt while ds/dt=√[(dy/dt)^2+(dx/dt)^2]
- arc length
- by Pythagorean theorem
- s=∫√1+(dy/dx)^2 dx =∫√1+(dx/dy)^2 dy --> introducing parameters s=∫√[(dx/dt)^2 + (dy/dt)^2] dt
- by Pythagorean theorem
- ∫six arcHF dx *
- integration by parts as we already can integrate u'(x)-- but still can not integrate u(1).
- ∫HF dx
- ∫sechx dx OR ∫cschx dx
- 工具: 1. e^x-->e^2x 2. FS 3. do reverse work
- 工具: 1. e^x-->e^2x 2. FS 3. do reverse work
- e.g. ∫sechx dx= ∫ 2/(e^x+e^-1) dx= ∫ 2e^x/(e^2x+1) dx=> reverse work <= FS: d/dx(2arctan(e^x))= 2e^x/(e^2x+1) -->∫sechx dx= 2artan(e^x) *
- ∫sinhx dx OR ∫coshx dx
- expressed in e^x form. then see.
- ∫tanhx dx OR ∫cothx dx
- derived formulas
- ∫sechx dx OR ∫cschx dx
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Información
- Descripción
- (FP3) MATHS Mapa Mental sobre HYPERBOLIC FUNCTIONS, creado por C D el 16/11/2017.
- Creado por
- C D
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