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Chapter 16

Umaimah Kazi English 14 cards

Chapter 16

Cards in this deck (14)

  1. 1Discovery of benzene-C:H ratio 1:1
    -Molecular formula- C6H6
    -Low C:H rations/conjugated/aromatic- has pleasant smell
  2. 2Addition of bromine to benzene: What catalyst is needed to add benzene? Substitution or addition reaction?When bromine adds to benzene, a catalyst such as FeBr3 is needed.
    The reaction that occurs is the substitution of a hydrogen by a bromine.
  3. 3Why does benzene undergo substitution with Br2 while cyclohexene undergoes an addition reaction?-Addition of Br2 to benzene is unfavorable. -It would result in a non-aromatic product.
    -Addition of Br2 to the double bond is not observed.
    Why does benzene undergo substitution with Br2 while cyclohexene undergoes an addition reaction?
  4. 4Resonance energy of Benzene-Benzene does not have the predicted heat of hydrogenation of –359 kJ/mol.
    -The observed heat of hydrogenation is
    –208 kJ/mol, a difference of 151 kJ.
    -This difference between the predicted and the observed value is called the resonance energy.
    (molar heats of hydrogenation)
  5. 5Resonance structures of benzene-Benzene is actually a resonance hybrid of the two Kekulé structures.
    -The C—C bond lengths in benzene are shorter than typical single-bond lengths, yet longer than typical double-bond lengths (bond order 1.5).
    Resonance structures of benzene
  6. 6Structure of Benzene-Each sp2 carbon has an unhybridized p orbital perpendicular to the ring that overlaps around the ring.
    -The six pi electrons are delocalized over the six carbons.
  7. 7Failure of Resonance Picture-All cyclic conjugated hydrocarbons were proposed to be aromatic.
    -However, cyclobutadiene is so reactive that it dimerizes before it can be isolated.
    -Cyclooctatetraene adds Br2 readily to the double bonds.
    Failure of Resonance Picture
  8. 8What are the MO rules for benzene?1. Six overlapping p orbitals must form six molecular orbitals (MOs).
    2. Three will be bonding, three antibonding.
    3. Lowest-energy MO will have all bonding interactions, no nodes.
    4. As energy of MO increases, the number of nodes increases.
  9. 9Draw out MOs for BenzeneDraw out MOs for Benzene
  10. 10First MO of benzene- is entirely bonding, no nodes
    -has very low energy because it has 6 bonding interactions and the electrons are delocalized over all 6 carbon atoms
  11. 11Intermediate MO of benzen-are degenerate (equal in energy) with 2 orbitals are each level
    -π2 & π3 have one nodal plane (each)
  12. 12All antibonding MO of benzene-The all antibonding π6* has 3 nodal planes
    -Each pair of adjacent P orbital is out of the phase in a destructive manner
  13. 13Describe the energy diagram of benzene- all bonding orbitals are filled "closed shell" -> extremely stable arrangement
    -6 π electrons fill 3 bonding π orbitals
  14. 14Draw MO of cyclobutadiene

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