Flashcards
Algebra II Chapter 1 Review
Cards in this deck (40)
- 11. DRAW THE DIAGRAM FOR REAL #SSEE MIND MAP (SEPARATE WITHIN ALGEBRA 2 TOPIC)
- 22. IS √ 5 A REAL NUMBERYES
- 33. IS 0 A NATURAL NUMBERNO
- 4<, >, OR = 4. 2 ______-22 > -2
- 5<, >, OR = 5. √ 0.7 _______.7√ 0.7 > .7
- 6<, >, OR = 6. √4 _______2√4 = 2
- 7<, >, OR = 7. 7_________3²7 < 3²
- 8FIND OPPOSITE AND RECIPROCAL √13-√13 ; 1/√13
- 9FIND OPPOSITE AND RECIPROCAL 4 1/2-4 1/2; 1/4.5
- 10simplify THE EXPRESSION |-3|3
- 11simplify THE EXPRESSION |2-13||-11| = 11
- 12simplify FOR THE GIVEN VARIABLE 2(X-Y) - 4(2Y+3X) X = -4; Y = 22(X-Y) - 4(2Y+3X)
2(-4-2) - 4(2(2)+3(-4))
2(-6) - 4(4-12)
-12 - 4(-8)
-12 - -32
-12 + 32
20 - 13simplify FOR THE GIVEN VARIABLE 9X - 7Y X = 1; Y = -59X - 7Y
9(1) - 7(-5)
9 - -35
9+35
44 - 14simplify BY COMBINING LIKE TERMS 4(X+2Y) - 4(X+Y)4(X+2Y) - 4(X+Y)
4X+8Y -4X-4Y
4Y - 15simplify BY COMBINING LIKE TERMS 8A - 6B + 9C + 2B - 2A + 2D - 4C8A - 6B + 9C + 2B - 2A + 2D - 4C
8A - 2A - 6B + 2B + 9C - 4C + 2D
6A - 4B + 5C + 2D - 16SOLVE EACH EQUATION 2X + 10 = 4X + 202X + 10 = 4X + 20
-4X -10 -4X - 10
-2X = 10
-2X/-2 = 10/-2
X = -5 - 17SOLVE EACH EQUATION 3(2-X) = 2(2X-4)3(2-X) = 2(2X-4)
6-3X = 4X-8
-6 -4X -4X -6
-7X = -14
-7X/-7 = -14/-7
X = 2 - 18Solve for x; find ANY restrictions x/2 + b = 1/ax/2 + b = 1/a
(2)(x/2) + (2)b = (1/a)(2)
x + 2b = 2/a
-2b = -2b
x = 2/a + 2b
restrictions: a cannot = 0 - 19Solve for x; find ANY restrictions xy -4x = 2xy -4x = 2
x( y-4) =2
x(y-4)/(y-4) = 2/(y-4)
x = 2/(y-4)
restrictions: y cannot = 4
(hint: denominator cannot equal 0) - 20Solve for x; find ANY restrictions xy + 2x = axy + 2x = a
x(y+2) = a
/(y+2) = /(y+2)
x = a/(y+2)
restrictions: y cannot = -2
(hint: denominator cannot equal 0) - 21Solve for x; find ANY restrictions x/4 + a = b/2x/4 + a = b/2
(4)(x/4) + (4)a = (4)(b/2)
x + 4a = 2b
-4a = -4a
x = 2b - 4a - 22The length of the sides of the rectangle are in the ratio of 2:6. The perimeter of the rectangle is 256 inches. Find the length of the sides.Perimeter of rectangle = 2b + 2H
(2)(x) + (6)(x) = 256
8x/8 = 256/8
x = 32
2(32) = 64
6(32) =192
64+192 = 256 - 23The length of the sides of a triangle are in the ratio of 2:3:4. The perimeter of the triangle is 90 inches. Find the length of the sides.2x + 3x + 4x = 90
9x /9 = 90/9
x = 10
2(10) = 20
3(10) = 30
4(10) = 40 - 24Solve each inequality. Graph solution 5(2-x) < 7-55(2-x) < 7-5
10 - 5x < 2
-10 -10
-5x/-5 < -8/-5
x > 8/5 or x > 1 3/5 - 25Solve each inequality. Graph solution 3 - 2t < -73 - 2t < -7
-3 -3
-2t/-2 < -10/-2
t > 5 - 26Solve each inequality. Graph solution 7x < 14 and 4x > -87x < 14 and 4x > -8
/7 < /7 and /4 > /4
x < 2 and x > -2
-2 < x < 2 - 27Solve each inequality. Graph solution 2(x+1) > 2x - 52(x+1) > 2x - 5
2x + 2 > 2x - 5
-2x - 2 > -2x -2
0 > -7 - 28Solve equation. Check for extraneous answers 5 + |7+x| = 35 + |7+x| = 3
-5 = -5
|7+x| = -2
no solution - 29Solve equation. Check for extraneous answers |x-6| = 5x + 2|x-6| = 5x + 2
x-6 = 5x +2 or x-6 = -5x-2
-x-2 = -x -2 or +5x +6 = +5x +6
-8/4 = 4x/4 or 6x/6 = 4/6
-2 = x or x = 2/3
|-2-6| = 5(-2)+2 or |2/3 - 6| = 5(2/3) +2
8 not = -5 or 16/3 = 16/3
solution 16/3 or 5 1/3 - 30Solve inequality. Graph solution |3x + 5| + 10 < 5|3x + 5| + 10 < 5
- 31Solve inequality. Graph solution |2x + 7 | > -1|2x + 7 | > -1
- 32Solve inequality. Graph solution 3|x+7| - 5 < 103|x+7| - 5 < 10
-5 -5
3|x+7| < 5
/3 /3
|x+7| < 5/3
x+7 < 5/3 or x+7 < -5/3
NOT FINISHED - 33Write each specification as an absolute value inequality 21 < c < 2921 < c < 29
(29+21)/2 = 25
(29-21)/2 = 4
-4 < c-25 < 4
|c-25| < 4 - 34Write each specification as an absolute value inequality 3 < c < 53 < c < 5
(5+3)/2 = 4
(5-3)/2 = 1
-1 < c - 4 < 1
|c - 4| < 1 - 35Solve probability In a bag, there are 10 blue marbles, 8 yellow, 12 red, and 20 green P (yellow)8/50 = 4/25
- 36Solve probability In a bag, there are 10 blue marbles, 8 yellow, 12 red, and 20 green P (Blue)10/50 = 1/5
- 37Solve probability In a bag, there are 10 blue marbles, 8 yellow, 12 red, and 20 green P (not green)30/50 = 3/5
- 38Solve probability In a bag of 40 marbles, there are 20 green, 8 black, and the rest are white P (white)12/40 = 3/10
- 39Solve probability In a bag of 40 marbles, there are 20 green, 8 black, and the rest are white P (not white)28/40 = 7/10
- 40Solve probability In a bag of 40 marbles, there are 20 green, 8 black, and the rest are white P (green)20/40 = 1/2
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- 10th grade Algebra II Flashcards on Algebra II Chapter 1 Review, created by tonya bell on 27/08/2022.
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