8649100
Description
Flashcards by Monika Bączek, updated more than 1 year ago
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Created by Monika Bączek
about 7 years ago
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| Question | Answer |
| \(a^{0}=\) | 1 |
| \(a^{n}*a^{m}=\) | \(a^{m+n}\) |
| \(a^{n}:a^{m}=\) | \(a^{m-n}\) |
| \((a^{n})^{m}=\) | \(a^{m*n}\) |
| \(a^{\frac {1}{n}}=\) | \(\sqrt[n]a\) |
| \(a^{\frac {k}{n}}=\) | \(\sqrt[n]a^{k}\) |
| \(log_{a}b=x \leftrightarrow \) | \(a^{x}=b\) |
| \(log_{a}b-log_{a}c=\) | \(log_{a}(\frac {b}{c})\) |
| \(log_{a}b^{c}=\) | \(c*log_{a}b\) |
| \(log_{a}b+log_{a}c=\) | \(log_{a}(b*c)\) |
| \((2^{-8})^{3}=\) | \(2^{-24}\) |
| \(17^{6}:17^{-3}=\) | \(17^{9}\) |
| \(15^{-3}*15^{-7}=\) | \(15^{-10}\) |
| \(6^{-5}:6^{-2}=\) | \(6^{-3}\) |
| \(2^{82}:4^{40}=\) | \(2^{2}\) |
| \(25^{3}*0,2^{-6}=\) | \(5^{12}\) |
| \(5^{8}:0,2^{-7}=\) | \(5\) |
| \(\frac {125^{3}*(5^{-2})^{4}}{25^{4}*25*^{-5}}=\) | \(125\) |
| \(\frac {7^{5}:49}{7}*(\frac {1}{7})^{-2}=\) | \(7^{4}\) |
| \(8^{\frac {1}{3}}=\) | 2 |
| \(144^{-\frac {1}{2}}=\) | \(\frac {1}{12}\) |
| \(64^{\frac {4}{3}}=\) | 256 |
| \(9^{-1,5}=\) | \(\frac {1}{27}\) |
| \(log_{2}32=\) | 5 |
| \(log_{7}1=\) | 0 |
| \(log10^{5}=\) | 10 |
| \(log_{2}80+log_{2}0,1=\) | 3 |
| \(log_{3}4,5+log_{3}2=\) | 2 |
| \(log_{2}7-log_{2}56=\) | -3 |
| \(log_{8}8^{\frac{1}{3}}=\) | \(\frac{1}{3}\) |
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