Flashcards
Potęgi,pierwiastki i logarytmy
Cards in this deck (30)
- 1\(a^{0}=\)1
- 2\(a^{n}*a^{m}=\)\(a^{m+n}\)
- 3\(a^{n}:a^{m}=\)\(a^{m-n}\)
- 4\((a^{n})^{m}=\)\(a^{m*n}\)
- 5\(a^{\frac {1}{n}}=\)\(\sqrt[n]a\)
- 6\(a^{\frac {k}{n}}=\)\(\sqrt[n]a^{k}\)
- 7\(log_{a}b=x \leftrightarrow \)\(a^{x}=b\)
- 8\(log_{a}b-log_{a}c=\)\(log_{a}(\frac {b}{c})\)
- 9\(log_{a}b^{c}=\)\(c*log_{a}b\)
- 10\(log_{a}b+log_{a}c=\)\(log_{a}(b*c)\)
- 11\((2^{-8})^{3}=\)\(2^{-24}\)
- 12\(17^{6}:17^{-3}=\)\(17^{9}\)
- 13\(15^{-3}*15^{-7}=\)\(15^{-10}\)
- 14\(6^{-5}:6^{-2}=\)\(6^{-3}\)
- 15\(2^{82}:4^{40}=\)\(2^{2}\)
- 16\(25^{3}*0,2^{-6}=\)\(5^{12}\)
- 17\(5^{8}:0,2^{-7}=\)\(5\)
- 18\(\frac {125^{3}*(5^{-2})^{4}}{25^{4}*25*^{-5}}=\)\(125\)
- 19\(\frac {7^{5}:49}{7}*(\frac {1}{7})^{-2}=\)\(7^{4}\)
- 20\(8^{\frac {1}{3}}=\)2
- 21\(144^{-\frac {1}{2}}=\)\(\frac {1}{12}\)
- 22\(64^{\frac {4}{3}}=\)256
- 23\(9^{-1,5}=\)\(\frac {1}{27}\)
- 24\(log_{2}32=\)5
- 25\(log_{7}1=\)0
- 26\(log10^{5}=\)10
- 27\(log_{2}80+log_{2}0,1=\)3
- 28\(log_{3}4,5+log_{3}2=\)2
- 29\(log_{2}7-log_{2}56=\)-3
- 30\(log_{8}8^{\frac{1}{3}}=\)\(\frac{1}{3}\)