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Application Differentiation and Integration in Circuit Analysis
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Application Differentiation and Integration in Circuit Analysis
Problem Statement : For the circuit in figure above, i(t)=4(2-e^(-10t)) mA. If i2(0)=-1mA, find: (a)i1(0), (b)v(t),v1(t) and v2(t) and (c)i1(t) and i2(t)
Differentiation equation of INDUCTOR
- From this equation, Voltage across inductor is product of inductance in Henry (H) and rate of change of current flow divide by rate of change of time
- From this equation, Voltage across inductor is product of inductance in Henry (H) and rate of change of current flow divide by rate of change of time
Integration equation of INDUCTOR
- Current-voltage relationship is the integration of voltage at initial time to specific time multiple by invert inductance and add by initial current across inductor
- Current-voltage relationship is the integration of voltage at initial time to specific time multiple by invert inductance and add by initial current across inductor
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- Mind Map on Application Differentiation and Integration in Circuit Analysis, created by G. CALLEN on 09/12/2017.
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- G. CALLEN
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