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Pair of Linear Equations in Two Variables

Mind map: Pair of linear equations in two variables
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Pair of Linear Equations in Two Variables
Geometric [Graphical] Solution
- Single and Unique Solution
- Intersecting lines
- Consistent
- If the Pair of Linear Equations are ax+by+c= 0 and Ax+By+C=0 then a/A ≠ b/B ≠ c/C
- Intersecting lines
- No solutions at all
- Parallel Lines
- Inconsistent
- If the Pair of Linear Equations are ax+by+c= 0 and Ax+By+C=0 then a/A = b/B ≠ c/C
- Parallel Lines
- Infinitely Many Solutions
- Identical or Overlapping Lines
- Consistent
- If the Pair of Linear Equations are ax+by+c= 0 and Ax+By+C=0 then a/A = b/B = c/C
- Identical or Overlapping Lines
- Single and Unique Solution
Algebraic Solution
- Substitution Method
- We Substitute the Value of one Variable by Expressing it in the Term of the Other Variable to Solve the Pair of Linear equations
- Elimination Method
- We Eliminate one Variable First to Get a Linear Equation in one Variable and Then Solving it we Find the other Variable
- Cross Multiplication Method
- If the Pair of Linear Equations are ax+by+c= 0 and Ax+By+C=0 then x/(b*-B*c)= y/(c*A-C*a)= 1/(a*B-A*b)
- Substitution Method
Equations Reducible to a Pair of Linear Equations
- in Pair of Equations with Variables in the Denominator we change the Fraction To Another Variable
- Eg. Let the Pair of Equations be 2/x+3/y= 13 and 5/x-4/y= -2
- We take (1/x) as 'p' and (1/y) as 'q'
- Then the Equations are 2p+3q=13 and 5p-4q=-2
- After solving for 'p' and 'q' we solve for (1/x)=p and (1/y)=q
- Then the Equations are 2p+3q=13 and 5p-4q=-2
- We take (1/x) as 'p' and (1/y) as 'q'
- Eg. Let the Pair of Equations be 2/x+3/y= 13 and 5/x-4/y= -2
- in Pair of Equations with Variables in the Denominator we change the Fraction To Another Variable
Information
- Description
- NCERT mathematics class 10 Chapter 3
- Created by
- JUDHAJEET GHOSH
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