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Unit 1 Functions
- 1.1
- A relation is a function if for each x-value has only one y-value
- an x-value with more than one y-value is not a function
- domain and range of a function can be found from the restrictions
- restrictions on the domain is found from a fraction function because you cannot simply sub an x value and divide by 0
- range is found if a y-value cannot exceed a certain point on the graph
- 1.2
- The symbol f(x) represents the dependent variable
- f indicates that it is a function and the outcome relies on what x equals
- it does not always need to be represented by f
- eg. f(x) = 3x
- if x = 1, then y = 3
- if x = 3, then y = 9
- f indicates that it is a function and the outcome relies on what x equals
- The symbol f(x) represents the dependent variable
- 1.3
- the a-value will determine whether there is a min or a max value
- a > 0 means there is a min value
- a < 0 means there is a max value
- finding the max or min of a quadratic function can be found by completing the square or partial factoring
- completing the square f(x) = a(x - h)² + k. The vertex is (h, k)
- Partial Factoring
- is simply when you find the mid point of 2 x values
- the a-value will determine whether there is a min or a max value
- 1.4
- when identical radicals are identical and are multiplying each other, they can be set as a full term
- √5 x √5 = 5
- Radicals follow the like term rule
- 4√2 - 2√2 = 2√2
- 5√2 + 4√2 = 9√2
- Values inside radicals can be broken apart into values that have the product of it
- √20 is same as √5 x √4
- when identical radicals are identical and are multiplying each other, they can be set as a full term
- 1.5
- Quadratic equations can be solved by
- Completing the Square
- Factoring
- using the quadratic formula
- the number of solutions to a quadratic equations and the number of roots of the related quadratic function can be determined using the discriminant
- b² - 4ac > 0 then there are 2 roots
- b² - 4ac < 0 then there are no roots
- b² - 4ac = 0 then there is only 1 root
- Quadratic equations can be solved by
- 1.6
- When the 2 roots are found and a point is given, the quadratic equation can be found
- the roots are placed into the factored form equation: y = a(x - r) (x - s)
- you can then sub in the 2 roots into r and s and isolate for a by subbing in the given point
- When given 1 root and a point on a function, the equation can still be found
- the process is the same but since there is only 1 root, the vertex is given so you would sub in the equation y = a(x - h)² + k and isolate for a
- When the 2 roots are found and a point is given, the quadratic equation can be found
- 1.7
- Some linear quadratics may intersect with others, the point of intersections can be found
- since the y-values will be the same, the two equations will equal each other
- then simplify each equation by setting the values to one side
- using the discriminant, the number of intersections will be found
- the same rules apply as if the discriminant was used to find the roots
- Some linear quadratics may intersect with others, the point of intersections can be found
- 1.1
Unit 2 Transformation
- 2.1
- complex functions can be the same as simpler functions
- You would first state any restrictions at the beginning
- Since in a fraction, if the denominator is 0, then the value is nothing. So restrictions must be assigned to certain values so that the denominator does not equal to 0
- 1 —— 2-x
- x ≠ 2
- 1 —— 2-x
- Since in a fraction, if the denominator is 0, then the value is nothing. So restrictions must be assigned to certain values so that the denominator does not equal to 0
- Then simplify the function fully
- Then state any restrictions
- You would first state any restrictions at the beginning
- complex functions can be the same as simpler functions
- 2.2
- 2.2 part 1
- if a function consist of division or multiplication between 2 fractions, then the process is different
- You would first state any restrictions at the beginning
- Simplify the function
- As you are simplifying the rational expressions, you have to state any restrictions each time you do a step
- 2.2 part 2
- if a function consists of addition or subtraction between 2 fractions, then the process is the same as 2.1, but you would have to do common denominator to do any simplifying
- 2.2 part 1
- Combinations of Transformations
- y = af (k (x - d) ) + c
- a-value
- The a affects the function by stretching or compressing vertically by a factor of a
- if the a-value is negative, there is a reflection along the x-axis
- d-value
- the d affects the function translation horizontally
- c-value
- the c affects the function translation vertically
- k-value
- the k affects the function by stretching or compressing horizontally by a factor of 1/k
- a-value
- y = af (k (x - d) ) + c
- inverse functions
- To put it simply, the domain and range is flipped
- This means the x-values and y-values are switched
- when forming the equation, you would switch the x and y variable and algebraically solve for y
- y = 4x + 2
- x = 4y + 2
- x and y are switched
- x - 2 —— = y 4
- y is isolated
- x - 2 —— = f-(x) 4
- the inverse function would be then replaced with f-(x)
- To put it simply, the domain and range is flipped
- Transformation equation
- original function co-ordinates
- (x/k) +d
- x from original function and k, d from equation
- ay + c
- y from original function and a, c from equation
- 2.1
Unit 3
- 3.1 and 3.2 and 3.4
- exponential functions are modeled by y = ab^2
- The function will increase if
- if a is positive and b > 1
- if 0 < b < 1 and a is negative
- The function will decrease if
- if 0 < b < 1 and a is positive
- if a is negative and b > 1
- b can determine the increasing and decreasing of the graph
- The function will increase if
- exponential functions are modeled by y = ab^2
- 3.3
- square roots means n = 2
- so if m = 1, you can also say a^1/2
- This can be very helpful in simplifying and expanding
- eg. if n = 2 and m = 4, then the rational expression will be a^2
- square roots means n = 2
- 3.5
- general equation for an exponential function is
- if d > 0, translate right if d < 0, translate left
- if c > 0, translate up if c < 0, translate down
- if a > 1, stretch vertically by a factor of a if 0 < a < 1, compress vertically by a factor of a if a < 0, reflect along the x-axis and stretch or compress
- if k > 1, compress horizontally by a factor of 1/k if 0 < k < 1, stretch horizontally by a factor of 1/k if k < 0, reflect along the y-axis and stretch or compress
- be aware that some exponential functions can be written in different bases but mean the same as others
- y = 2^4x is same as y = 16^x
- a horizontal asymptote is a line where it never goes to a natural number and always a fraction
- Horizontal asymptote y = c
- general equation for an exponential function is
- Doubling, half life, and other problems
- you can use the exponential functions to determine half life or doubling in a period of time
- eg. there is 1 bacteria. The population of bacteria doubles every 3 hours
- variable a would be the starting population 1
- m would be the the ratio, in this case it is 2
- since it is every 3 hours, we would not set n to 3. We would write the exponent of t/n and sub n there
- y = a(m)^n would be the equation
- sometimes n is replaced with t/n because if the time frame each action is done
- eg. there is 1 bacteria. The population of bacteria doubles every 3 hours
- you can use the exponential functions to determine half life or doubling in a period of time
- 3.1 and 3.2 and 3.4
Unit 4 Trigonometry
- 4.1
- Unit Circle
- The unit circle is a circle with a centre at the origin and a radius of 1 unit
- if you consider the triangle within the unit circle, you can state the primary trigonometric ratios easily
- Opposite Sinθ = ———— Hypotenuse
- Adjacent Cosθ = ———— Hypotenues
- Opposite Tanθ = ———— Adjacent
- Special triangles
- Exact Trigonometric ratios for special angles can be determined using special triangles
- Unit Circle
- 4.2
- Alternatively, you would be given angles that are at different quadrants, and each quadrants have negative and positive trigonometric ratios
- if you were given an angle higher than 90°
- but related angles can refer back to a reference angle
- eg. 120° can be referenced to 60°
- eg. 120° can be referenced to 60°
- Once you have the reference trigonometric ratios, you can determine which are negative using the CAST method
- Each Quadrant represent which trigonometric ratio will be positive and the rest will be negative, however if the trigonometric is at quadrant 1, as you can see quadrant 1 is labelled as A (All) so all trigonometric ratios will be positive
- Alternatively, you would be given angles that are at different quadrants, and each quadrants have negative and positive trigonometric ratios
- 4.3
- Reciprocal Trigonometric Ratios are defined as follows
- Reciprocal Trigonometric Ratios are defined as follows
- 4.4 and 4.5
- An important note to keep in mind are the ambiguous cases of the sine law
- Acute Trangles
- if a ≥ b, one triangle exists
- if a < b and a < bsinA, no Triangle exists
- if a < b and a = bsinA, one Triangle exists
- if a < b and a > bsinA, 2 triangles exists
- Obtuse Triangles
- if a ≤ b, no triangles exists
- if a > b, one triangle exists
- Acute Trangles
- When solving 2d and 3d questions, often refer back to sine law, cosine law and special triangles
- An important note to keep in mind are the ambiguous cases of the sine law
- 4.5
- Trigonometric Identities require a high algebraic level of skill. As long as you know the following trig identities, more complicated trig identities can be solved.
- Trigonometric Identities require a high algebraic level of skill. As long as you know the following trig identities, more complicated trig identities can be solved.
- 4.1
Unit 5 Trig Functions
- 5.1
- a period is the horizontal distance of one cycle on a graph
- Periodic function has a pattern of y-value that repeats at regular intervals
- axus if the curve is a horizontal line that is hallf-way between the max and min
- Phas shift is the horizontal shift of a graph from its original position
- finding the period would be getting 2 x co-ordinate of the max or min of the cycle. you would then subtract each other finding the period
- the formula for finding amplitude
- max - min y = ————— 2
- equation of the axis
- max + min y = ————— 2
- 5.2
- Graphing a sine function are based on these key co-ordinates because we can use the trigonometric ratios of special triangles. The same goes for cosine functions
- Sine Graph | | | | | | | | |
- Cosine Graph | | | | | | | | |
- 5.3 and 5.4
- y = a Sin[k (x-d)] + c
- a - amplitude k - period d - horizontal transition c - verticle transition
- y = a Cos[k (x - d)] +c
- 360 period = ——— |K|
- 5.1
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- 11 Mathematics Mind Map on MCR3UO - Billy, created by Billy Nguyen on 19/06/2017.
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- Billy Nguyen · Jun 2017
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- Jun 19, 2017
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