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Group 2 and Group 7 Chemistry

Mind map: Group 2 and Group 7 chemistry
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Group 2 and Group 7 Chemistry
Group 2
- Electron Configuration:
- Always end in the s2 orbital
- This is because the highest energy subshell that its most outer electron is in is the s orbital
- Always end in the s2 orbital
- Atom size
- Increases as you go down the group because of more shielding, more distance.
- This is because there are more electrons which require more shells
- Increases as you go down the group because of more shielding, more distance.
- Bonding
- Usually have metallic bonding between each other
- Electrostatic forces of attraction between cations and a sea of delocalised electrons
- Usually have metallic bonding between each other
- Melting Points:
- Decrease as you go down the group
- Cations have the same charge, but shielding and distance increase
- This means there is a weaker nuclear attraction
- This means, as you go down the group, it's easier to overcome the electrostatic forces of attraction
- This means there is a weaker nuclear attraction
- Cations have the same charge, but shielding and distance increase
- Decrease as you go down the group
- Ionisation energies
- Decrease as you go down the group
- This is because shielding increases, and so does distance
- This leads to a weaker nuclear attraction and makes it easier to get rid of an electron
- This is because shielding increases, and so does distance
- Decrease as you go down the group
- Reaction with water
- As you go down the group, reactivity increases:
- This is because there's more shielding, more distance, weaker nuclear attraction and so it's easier to lose electrons
- Group 2 elements will always react with water to give a metal hydroxide and hydrogen gas
- Mg + H2O(l) -----> Mg(OH)2 + H2(g)
- Magnesium with steam will give you a different product
- Mg(s) + H2O(g) -------> MgO + H2(g)
- This reaction is not so vigorous
- Magnesium with steam will give you a different product
- Ca + H2O(l)----> Ca(OH)2 + H2(g)
- And so on.. The reactions get more and more vigorous as you go on
- Solubility of the group 2 hydroxides
- As you go down the group, the group 2 hydroxides get more and more soluble
- Mg(OH)2 is the most insoluble, it forms a white precipitate, and is known as a suspnsion in water
- Ba(OH)2 is the most soluble and forms a clear solution
- The reason for this is because as you go down the group, there is weaker nuclear attraction between the hydroxide ion and the group 2 ion and so they seperate easily in water
- As you go down the group, the solution formed gets more alkaline because there are more OH ions free in the solution
- As you go down the group, the group 2 hydroxides get more and more soluble
- Uses of the hydroxides:
- The hydroxides can be used to neutralise acids to give a salt and water
- Magnesium hydroxide is used to neutralise stomach acid.
- A weak hydroxide is used because we don't want to neutralise all the stomach acid
- Magnesium carbonate does the same job but leads to the build up of gas in the stomach
- Calcium hydroxide can be used to neutralise acidity in soil by farmers
- It's a stronger alkaline than Mg(OH) so does a faster job
- AKA Slaked lime
- Magnesium hydroxide is used to neutralise stomach acid.
- The hydroxides can be used to neutralise acids to give a salt and water
- As you go down the group, reactivity increases:
- Solubility of the group 2 sulphates
- They get more and more insoluble as you go doen the group
- i.e. Magnesium sulphate is the most soluble and forms a clear solution
- Barium sulphate is the most insoluble and form a white precipitate
- We can use BaSO4 as a Barium meal
- It's swallowed and because it's dense, it is able to absorb x-ray.
- This helps to show soft tissue such as your gut
- Although barium ions are toxic, it is still used because its so hard to seperate it from the sulphate ion
- This helps to show soft tissue such as your gut
- It's swallowed and because it's dense, it is able to absorb x-ray.
- We can use BaSO4 as a Barium meal
- Barium sulphate is the most insoluble and form a white precipitate
- i.e. Magnesium sulphate is the most soluble and forms a clear solution
- Test for Sulphate ions:
- You can add something that will give you barium ions such as BaCl2
- It will form a white precipitate of BaSO4 if the sulphate ions are present
- Similarly, this can be done the opposite way to test for Ba2+ ions as it will give the same result
- Problem: BaCO3 also gives a white precipitate
- This can be solved by adding dilute nitric acid first to get rid of the carbonate and hydroxide ions
- It will give carbon dioxide and water as a product
- This can be solved by adding dilute nitric acid first to get rid of the carbonate and hydroxide ions
- It will form a white precipitate of BaSO4 if the sulphate ions are present
- You can add something that will give you barium ions such as BaCl2
- They get more and more insoluble as you go doen the group
- Electron Configuration:
Group 7
- Electron Configuration
- Always end in p5
- F2-- Yellow vapour
- Cl2- Green gas
- Br2- Orange liquid and Brown gas
- I2- Black solid, Purple gas
- Size of atom: Increases as you go down the group
- More electrons, more shells, bigger atom
- Electronegativity:
- Decreases as you go down the group
- This is because there's more shielding and more distance, weaker nuclear attraction, so weaker ability to pull electron towards it
- Decreases as you go down the group
- Melting points:Increase as you go down the group
- More electrons, bigger atoms, more van der Waals formed, more energy required to overcome these van der Waal's
- Bond Strength: Decreases as you go down a group
- Because of more shielding and weaker nuclear attraction which means it's easier to break the bond
- Exception: Fluorine
- It's a very small atom and so you have more electrons within a smaller space
- There is repulsion and so the bond breaks easily
- It's a very small atom and so you have more electrons within a smaller space
- Reactions:
- Displacement/ Oxidising ability
- If something is an oxidising agent, then the element itself is going to be reduced.
- In other words, it's going to gain electrons
- The ability of a group 7 element to gain an electron decreases as you go down the group
- This is because, there is more shielding and weaker nuclear attraction and you go down the group
- Displacement reactions are redox reactions where the halogen acts as the oxidisng agent
- A more reactive halogen will displace a less reactive halogen
- e.g. 2NaBr + Cl2-------> 2NaCl + Br2
- e.g. NaBr + I2-------> NaBr + I2
- I2 is less reactive so there will be no change
- Cl2 is more reactive than Br so it will be displaced
- e.g. NaBr + I2-------> NaBr + I2
- e.g. 2NaBr + Cl2-------> 2NaCl + Br2
- A more reactive halogen will displace a less reactive halogen
- Displacement reactions are redox reactions where the halogen acts as the oxidisng agent
- This is because, there is more shielding and weaker nuclear attraction and you go down the group
- The ability of a group 7 element to gain an electron decreases as you go down the group
- In other words, it's going to gain electrons
- If something is an oxidising agent, then the element itself is going to be reduced.
- Reducing ability
- Here, the halide ions act as reducing agents, meaning they make something else gain electrons so they themselves must have lost electrons
- As you go down the group, the ability to lose electrons gets stronger as nuclear attraction gets weaker
- In other words, as you go down the group, the reducing ability of the halides gets stronger
- As you go down the group, the ability to lose electrons gets stronger as nuclear attraction gets weaker
- We can test the reducing ability of a group 7 element by reacting it with concentrated sulphuric acid
- When we react H2SO4 with NaCl, we get a normal acid/base reaction:
- H2SO4 + NaCl-----> HCl + NaHSO4
- The oxidation state of the sulphur hasn't changed: It starts off as 6 and ends as 6. All the oxidation states are the same
- This proves that the chloride ion is not a good reducing agent
- The oxidation state of the sulphur hasn't changed: It starts off as 6 and ends as 6. All the oxidation states are the same
- H2SO4 + NaCl-----> HCl + NaHSO4
- When we react with a bromide ion we get:
- H2SO4 + NaBr ------> HBr + NaHSO4
- HBr gives off misty fumes
- But then the HBr reacts further with the H2SO4
- HBr + H2SO4 -------> H2O + Br2 + SO2
- The oxidation state of the Br has gone from -1 to 0. It has lost electrons i.e. been oxidised
- The oxidation state of the sulphur has gone from +6 to +4 meaning it has gained 3 electrons i.e. been reduced
- Half Equations:
- 2Br- ------> Br2 + 2e-
- H2SO4 + 2e- + 2H+ --------> SO2 + 2H2O
- Overall Equation
- H2SO4 + 2H+ +2Br- ------> SO2 + 2H2O + Br2
- Overall Equation
- H2SO4 + 2e- + 2H+ --------> SO2 + 2H2O
- 2Br- ------> Br2 + 2e-
- Observations:
- HBr- Mistry fumes
- Br2- Brown gas, orange liquid
- SO2- Misty fumes
- The oxidation state of the Br has gone from -1 to 0. It has lost electrons i.e. been oxidised
- HBr + H2SO4 -------> H2O + Br2 + SO2
- H2SO4 + NaBr ------> HBr + NaHSO4
- When we react with the Iodide ion: We get the same thing as the bromide ion (Further reaction)
- However, for the products we get H2S
- Half Equations:
- 2I- -----> I2 + 2E-
- H2SO4 + 8H+ + 8e- -----> H2S + 4H2O
- Overall equation:
- 8I- + H2SO4 + 8H+-----> 4I2 + H2S + 4H2O
- Observation:
- HI - Misty fumes
- H2S - Rotten egg smell
- I2- Black solid, purple vapour
- H2S - Rotten egg smell
- HI - Misty fumes
- You may occasionally get S (yellow solid)
- Half Equations:
- Iodide is a better reducing agent than Br because it made S gain more electrons
- However, for the products we get H2S
- When we react H2SO4 with NaCl, we get a normal acid/base reaction:
- Here, the halide ions act as reducing agents, meaning they make something else gain electrons so they themselves must have lost electrons
- Displacement/ Oxidising ability
- Testing for Halide ions:
- 1. Add dilute nitric acid
- 2. Add Silver nitrate (AgNO3)
- AgCl- A white precipitate
- AgBr- A cream precipitate
- AgI- A pale yellow precipitate
- Further Test:
- Add dilute ammonia
- AgCl will dissolve, the others will not
- Add conc ammonia:
- Both AgBr and AgCl will dissolve, AgI will not
- AgI is insoluble in ammonia
- Add dilute ammonia
- To get rid of any hydroxide or carbonate ions
- 2. Add Silver nitrate (AgNO3)
- 1. Add dilute nitric acid
- Uses of Chlorine:
- Reaction with water:
- H2O + Cl2-----> HClO + HCl
- HClO is a disinfectant
- An oxidisng agent
- This is a disproportionation reaction where the Cl has been both oxidised and reduced
- HClO is a disinfectant
- In the presence of UV light:
- 2H2O + 2Cl2-----> 4HCl + O2
- Isn't safe in swimming pools due to acidity
- 2H2O + 2Cl2-----> 4HCl + O2
- H2O + Cl2-----> HClO + HCl
- Reaction with NaOH:
- NaOH + Cl2-----> NaClO + NaCl + H2O
- Also a disproportionation reaction
- Sodium chlorate: active ingredient in bleach
- The oxidising agent
- Safer to use in pools because:
- NaClO + H2O-----> NaOH + HClO
- NaOH + Cl2-----> NaClO + NaCl + H2O
- Reaction with water:
- Electron Configuration
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- Mind Map on Group 2 and Group 7 Chemistry, created by bilkis-21 on 29/05/2014.
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