This is because the highest energy subshell that its most outer electron is in is the s orbital
Atom size
Increases as you go down the group because of more shielding, more distance.
This is because there are more electrons which require more shells
Bonding
Usually have metallic bonding between each other
Electrostatic forces of attraction between cations and a sea of delocalised electrons
Melting Points:
Decrease as you go down the group
Cations have the same charge, but shielding and distance increase
This means there is a weaker nuclear attraction
This means, as you go down the group, it's easier to overcome the electrostatic forces of attraction
Ionisation energies
Decrease as you go down the group
This is because shielding increases, and so does distance
This leads to a weaker nuclear attraction and makes it easier to
get rid of an electron
Reaction with water
As you go down the group, reactivity increases:
This is because there's more shielding, more distance, weaker nuclear attraction and so it's easier to lose electrons
Group 2 elements will always react with water to
give a metal hydroxide and hydrogen gas
Mg + H2O(l) -----> Mg(OH)2 + H2(g)
Magnesium with steam will give you a different product
Mg(s) + H2O(g) -------> MgO + H2(g)
This reaction is not so vigorous
Ca + H2O(l)----> Ca(OH)2 + H2(g)
And so on.. The reactions get more and
more vigorous as you go on
Solubility of the group 2 hydroxides
As you go down the group, the group 2 hydroxides get more and more soluble
Mg(OH)2 is the most insoluble, it forms a white precipitate, and is known as a suspnsion in water
Ba(OH)2 is the most soluble and forms a clear solution
The reason for this is because as you go down the group, there is
weaker nuclear attraction between the hydroxide ion and the group 2
ion and so they seperate easily in water
As you go down the group, the solution formed gets
more alkaline because there are more OH ions free
in the solution
Uses of the hydroxides:
The hydroxides can be used to neutralise
acids to give a salt and water
Magnesium hydroxide is used to neutralise stomach acid.
A weak hydroxide is used because we don't want to neutralise all the stomach acid
Magnesium carbonate does the same job but leads to the build up of gas in the stomach
Calcium hydroxide can be used to neutralise acidity in soil by farmers
It's a stronger alkaline than Mg(OH) so does a faster job
AKA Slaked lime
Solubility of the group 2 sulphates
They get more and more insoluble as you go doen the group
i.e. Magnesium sulphate is the most soluble and forms a clear solution
Barium sulphate is the most insoluble and form a white precipitate
We can use BaSO4 as a Barium meal
It's swallowed and because it's dense, it is able to absorb x-ray.
This helps to show soft tissue such as your gut
Although barium ions are toxic, it is still used because
its so hard to seperate it from the sulphate ion
Test for Sulphate ions:
You can add something that will give you barium ions such as BaCl2
It will form a white precipitate of BaSO4 if the sulphate ions are present
Similarly, this can be done the opposite way to test for
Ba2+ ions as it will give the same result
Problem: BaCO3 also gives a white precipitate
This can be solved by adding dilute nitric acid first to
get rid of the carbonate and hydroxide ions
It will give carbon dioxide and water as a product
Group 7
Electron Configuration
Always end in p5
F2-- Yellow vapour
Cl2- Green gas
Br2- Orange liquid and Brown gas
I2- Black solid, Purple gas
Size of atom: Increases as you go down the group
More electrons, more shells, bigger atom
Electronegativity:
Decreases as you go down the group
This is because there's more shielding and more distance, weaker nuclear
attraction, so weaker ability to pull electron towards it
Melting points:Increase as you go down the group
More electrons, bigger atoms, more van der Waals formed, more
energy required to overcome these van der Waal's
Bond Strength: Decreases as you go down a group
Because of more shielding and weaker nuclear
attraction which means it's easier to break the bond
Exception: Fluorine
It's a very small atom and so you have more electrons within a smaller space
There is repulsion and so the bond breaks easily
Reactions:
Displacement/ Oxidising ability
If something is an oxidising agent, then the
element itself is going to be reduced.
In other words, it's going to gain electrons
The ability of a group 7 element to gain an
electron decreases as you go down the group
This is because, there is more shielding and weaker
nuclear attraction and you go down the group
Displacement reactions are redox reactions
where the halogen acts as the oxidisng agent
A more reactive halogen will displace a less reactive halogen
e.g. 2NaBr + Cl2-------> 2NaCl + Br2
e.g. NaBr + I2-------> NaBr + I2
I2 is less reactive so there will be no change
Cl2 is more reactive than Br
so it will be displaced
Reducing ability
Here, the halide ions act as reducing agents,
meaning they make something else gain electrons
so they themselves must have lost electrons
As you go down the group, the ability to lose
electrons gets stronger as nuclear attraction gets
weaker
In other words, as you go down the group, the
reducing ability of the halides gets stronger
We can test the reducing ability of a group
7 element by reacting it with concentrated
sulphuric acid
When we react H2SO4 with NaCl, we get a
normal acid/base reaction:
H2SO4 + NaCl-----> HCl + NaHSO4
The oxidation state of the sulphur hasn't changed:
It starts off as 6 and ends as 6. All the oxidation
states are the same
This proves that the chloride ion is not a
good reducing agent
When we react with a bromide ion we get:
H2SO4 + NaBr ------> HBr + NaHSO4
HBr gives off misty
fumes
But then the HBr reacts further with
the H2SO4
HBr + H2SO4 -------> H2O + Br2 + SO2
The oxidation state of the Br has gone from
-1 to 0. It has lost electrons i.e. been oxidised
The oxidation state of the sulphur has gone from +6 to
+4 meaning it has gained 3 electrons i.e. been reduced
Half Equations:
2Br- ------> Br2 + 2e-
H2SO4 + 2e- + 2H+ --------> SO2 + 2H2O
Overall Equation
H2SO4 + 2H+ +2Br- ------> SO2 + 2H2O + Br2
Observations:
HBr- Mistry fumes
Br2- Brown gas, orange liquid
SO2- Misty fumes
When we react with the Iodide ion: We
get the same thing as the bromide ion
(Further reaction)
However, for the products we get H2S
Half Equations:
2I- -----> I2 + 2E-
H2SO4 + 8H+ + 8e- -----> H2S + 4H2O
Overall equation:
8I- + H2SO4 + 8H+-----> 4I2 + H2S + 4H2O
Observation:
HI - Misty fumes
H2S - Rotten egg smell
I2- Black solid, purple vapour
You may occasionally get S (yellow solid)
Iodide is a better reducing agent than Br
because it made S gain more electrons
Testing for Halide ions:
1. Add dilute nitric acid
2. Add Silver nitrate (AgNO3)
AgCl- A white precipitate
AgBr- A cream precipitate
AgI- A pale yellow precipitate
Further Test:
Add dilute ammonia
AgCl will dissolve, the others will not
Add conc ammonia:
Both AgBr and AgCl will dissolve, AgI will not
AgI is insoluble in ammonia
To get rid of any hydroxide or carbonate ions
Uses of Chlorine:
Reaction with water:
H2O + Cl2-----> HClO + HCl
HClO is a disinfectant
An oxidisng agent
This is a disproportionation
reaction where the Cl has been
both oxidised and reduced