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Group 2 and Group 7 Chemistry

bilkis-21 English

Mind map about Group 2 and Group 7 chemistry: electron configuration, melting points, halide ions and uses of chlorine

Mind map: Group 2 and Group 7 chemistry

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Group 2 and Group 7 Chemistry

  1. Group 2

    • Electron Configuration:
      • Always end in the s2 orbital
        • This is because the highest energy subshell that its most outer electron is in is the s orbital
    • Atom size
      • Increases as you go down the group because of more shielding, more distance.
        • This is because there are more electrons which require more shells
    • Bonding
      • Usually have metallic bonding between each other
        • Electrostatic forces of attraction between cations and a sea of delocalised electrons
    • Melting Points:
      • Decrease as you go down the group
        • Cations have the same charge, but shielding and distance increase
          • This means there is a weaker nuclear attraction
            • This means, as you go down the group, it's easier to overcome the electrostatic forces of attraction
    • Ionisation energies
      • Decrease as you go down the group
        • This is because shielding increases, and so does distance
          • This leads to a weaker nuclear attraction and makes it easier to get rid of an electron
    • Reaction with water
      • As you go down the group, reactivity increases:
        • This is because there's more shielding, more distance, weaker nuclear attraction and so it's easier to lose electrons
      • Group 2 elements will always react with water to give a metal hydroxide and hydrogen gas
      • Mg + H2O(l) -----> Mg(OH)2 + H2(g)
        • Magnesium with steam will give you a different product
          • Mg(s) + H2O(g) -------> MgO + H2(g)
        • This reaction is not so vigorous
      • Ca + H2O(l)----> Ca(OH)2 + H2(g)
        • And so on.. The reactions get more and more vigorous as you go on
      • Solubility of the group 2 hydroxides
        • As you go down the group, the group 2 hydroxides get more and more soluble
          • Mg(OH)2 is the most insoluble, it forms a white precipitate, and is known as a suspnsion in water
          • Ba(OH)2 is the most soluble and forms a clear solution
          • The reason for this is because as you go down the group, there is weaker nuclear attraction between the hydroxide ion and the group 2 ion and so they seperate easily in water
            • As you go down the group, the solution formed gets more alkaline because there are more OH ions free in the solution
      • Uses of the hydroxides:
        • The hydroxides can be used to neutralise acids to give a salt and water
          • Magnesium hydroxide is used to neutralise stomach acid.
            • A weak hydroxide is used because we don't want to neutralise all the stomach acid
            • Magnesium carbonate does the same job but leads to the build up of gas in the stomach
          • Calcium hydroxide can be used to neutralise acidity in soil by farmers
            • It's a stronger alkaline than Mg(OH) so does a faster job
            • AKA Slaked lime
    • Solubility of the group 2 sulphates
      • They get more and more insoluble as you go doen the group
        • i.e. Magnesium sulphate is the most soluble and forms a clear solution
          • Barium sulphate is the most insoluble and form a white precipitate
            • We can use BaSO4 as a Barium meal
              • It's swallowed and because it's dense, it is able to absorb x-ray.
                • This helps to show soft tissue such as your gut
                  • Although barium ions are toxic, it is still used because its so hard to seperate it from the sulphate ion
      • Test for Sulphate ions:
        • You can add something that will give you barium ions such as BaCl2
          • It will form a white precipitate of BaSO4 if the sulphate ions are present
            • Similarly, this can be done the opposite way to test for Ba2+ ions as it will give the same result
            • Problem: BaCO3 also gives a white precipitate
              • This can be solved by adding dilute nitric acid first to get rid of the carbonate and hydroxide ions
                • It will give carbon dioxide and water as a product
  2. Group 7

    • Electron Configuration
      • Always end in p5
    • F2-- Yellow vapour
    • Cl2- Green gas
    • Br2- Orange liquid and Brown gas
    • I2- Black solid, Purple gas
    • Size of atom: Increases as you go down the group
      • More electrons, more shells, bigger atom
    • Electronegativity:
      • Decreases as you go down the group
        • This is because there's more shielding and more distance, weaker nuclear attraction, so weaker ability to pull electron towards it
    • Melting points:Increase as you go down the group
      • More electrons, bigger atoms, more van der Waals formed, more energy required to overcome these van der Waal's
    • Bond Strength: Decreases as you go down a group
      • Because of more shielding and weaker nuclear attraction which means it's easier to break the bond
      • Exception: Fluorine
        • It's a very small atom and so you have more electrons within a smaller space
          • There is repulsion and so the bond breaks easily
    • Reactions:
      • Displacement/ Oxidising ability
        • If something is an oxidising agent, then the element itself is going to be reduced.
          • In other words, it's going to gain electrons
            • The ability of a group 7 element to gain an electron decreases as you go down the group
              • This is because, there is more shielding and weaker nuclear attraction and you go down the group
                • Displacement reactions are redox reactions where the halogen acts as the oxidisng agent
                  • A more reactive halogen will displace a less reactive halogen
                    • e.g. 2NaBr + Cl2-------> 2NaCl + Br2
                      • e.g. NaBr + I2-------> NaBr + I2
                        • I2 is less reactive so there will be no change
                      • Cl2 is more reactive than Br so it will be displaced
      • Reducing ability
        • Here, the halide ions act as reducing agents, meaning they make something else gain electrons so they themselves must have lost electrons
          • As you go down the group, the ability to lose electrons gets stronger as nuclear attraction gets weaker
            • In other words, as you go down the group, the reducing ability of the halides gets stronger
        • We can test the reducing ability of a group 7 element by reacting it with concentrated sulphuric acid
          • When we react H2SO4 with NaCl, we get a normal acid/base reaction:
            • H2SO4 + NaCl-----> HCl + NaHSO4
              • The oxidation state of the sulphur hasn't changed: It starts off as 6 and ends as 6. All the oxidation states are the same
                • This proves that the chloride ion is not a good reducing agent
          • When we react with a bromide ion we get:
            • H2SO4 + NaBr ------> HBr + NaHSO4
              • HBr gives off misty fumes
              • But then the HBr reacts further with the H2SO4
                • HBr + H2SO4 -------> H2O + Br2 + SO2
                  • The oxidation state of the Br has gone from -1 to 0. It has lost electrons i.e. been oxidised
                    • The oxidation state of the sulphur has gone from +6 to +4 meaning it has gained 3 electrons i.e. been reduced
                    • Half Equations:
                      • 2Br- ------> Br2 + 2e-
                        • H2SO4 + 2e- + 2H+ --------> SO2 + 2H2O
                          • Overall Equation
                            • H2SO4 + 2H+ +2Br- ------> SO2 + 2H2O + Br2
                  • Observations:
                    • HBr- Mistry fumes
                    • Br2- Brown gas, orange liquid
                    • SO2- Misty fumes
          • When we react with the Iodide ion: We get the same thing as the bromide ion (Further reaction)
            • However, for the products we get H2S
              • Half Equations:
                • 2I- -----> I2 + 2E-
                • H2SO4 + 8H+ + 8e- -----> H2S + 4H2O
                • Overall equation:
                  • 8I- + H2SO4 + 8H+-----> 4I2 + H2S + 4H2O
              • Observation:
                • HI - Misty fumes
                  • H2S - Rotten egg smell
                    • I2- Black solid, purple vapour
              • You may occasionally get S (yellow solid)
            • Iodide is a better reducing agent than Br because it made S gain more electrons
    • Testing for Halide ions:
      • 1. Add dilute nitric acid
        • 2. Add Silver nitrate (AgNO3)
          • AgCl- A white precipitate
          • AgBr- A cream precipitate
          • AgI- A pale yellow precipitate
          • Further Test:
            • Add dilute ammonia
              • AgCl will dissolve, the others will not
              • Add conc ammonia:
                • Both AgBr and AgCl will dissolve, AgI will not
                • AgI is insoluble in ammonia
        • To get rid of any hydroxide or carbonate ions
    • Uses of Chlorine:
      • Reaction with water:
        • H2O + Cl2-----> HClO + HCl
          • HClO is a disinfectant
            • An oxidisng agent
          • This is a disproportionation reaction where the Cl has been both oxidised and reduced
        • In the presence of UV light:
          • 2H2O + 2Cl2-----> 4HCl + O2
            • Isn't safe in swimming pools due to acidity
      • Reaction with NaOH:
        • NaOH + Cl2-----> NaClO + NaCl + H2O
          • Also a disproportionation reaction
          • Sodium chlorate: active ingredient in bleach
            • The oxidising agent
          • Safer to use in pools because:
            • NaClO + H2O-----> NaOH + HClO

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Mind Map on Group 2 and Group 7 Chemistry, created by bilkis-21 on 29/05/2014.
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