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GCSE Maths Symbols, Equations & Formulae

livvy_hurrell

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Algebra for James

Description

Basic example of rearranging an equation to make one variable the subject

Note by Domhnall Murphy, updated more than 1 year ago

	Created by Domhnall Murphy about 7 years ago

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Resource summary

Page 1

$2a=b-c\left( \frac{b}{3} - 4 \right)$

Multiply out the bracket:

$2a=b - \frac{c.b}{3} + 4c$

Move terms containing $b$ to one side:

$\frac{c.b}{3} - b = 4c - 2a$

Split $b$ out as a factor on the LHS:

$b \left( \frac{c}{3} - 1 \right) = 4c - 2a$

Tidy up the LHS (i.e. express the bracketed term as a single fraction):

$b \left( \frac{c - 3}{3} \right) = 4c - 2a$

Multiply across the equation by $\frac{3}{c-3}$ :

$b = \frac{3}{c-3} \left( 4c - 2a \right)$

Finally leaving:

$b = 6\left( \frac{2c - a}{c-3} \right)$

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