Notas
Sample Mean Comparisons

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Página 1
The graph has to be in range with the mean at 37.72 since the sample distribution of n = 35 has the same mean as the population.
Based on the standard deviation sigma/n^0.5 = 2.71, the skinnier distribution makes most sense

Página 2
Location of the score 40 on distribution relative to the mean 37.71 --> Requires calculation z score to normalize the score of 40
- avg. score = 40
- SE Mean(n=35)= 37.71
- SE Standard Error = 2.71
Z score(M=40) = (40-37.71)/2.71 = 0.84
The Bieber Tweeter's are 0.84 sigmas away from the mean
Z Table probability = 1-0.7995 = 0.2005
There is a chance of 20.05% of a Klout score above 40

Página 3
Scientific standardization measures of likely vs. unlikely
Find standard error (SE) for n = 250 and sigma 16.04
SE (std. deviation of sample) = 1.01
Z score = 2.24
Z table = 1-0.9881 = 0.0119 = 1.2%

Página 4
Experiment randomization of cloud scores as stated below:
640
789, 124, 521, 9, 982
65, 313, 821, 42, 59, 129, 952, 1023, 421, 777
Mean = 43,89
Mean = 47,65
Mean = 36,07

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- TEFL Data Analyst (Lesson 7 - Sampling Distributions) Notas sobre Sample Mean Comparisons, criado por Simon Dman em 29-04-2020.
- Criado por
- Simon Dman
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