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- 1∫xcosxdxF´ =cos x g=x
F=sen x g=1
∫ cos x= sen -∫sen x dx
X sen x + cos x +c - 2∫ x/cos^2 x dxF´ = 1/cos^2 x g=x
F=tan x g´=1
∫ 1/(cos〖^2〗) dx= tang - ∫ tang x dx=x tang + (sen x )/cosx
X Tang x + In (cosx) + c - 3∫ sen x In (cos x) dx∫ sen x In (cos x) dx
F´= Sen x g= In(cos x)
F= cos x g= (sen x )/cosx
∫ sen x In (cos x ) dx = - cos x In (cos x) - ∫ sen x dx
Cos x In (cos x) + cos x + c - 4∫ x/cos^2 dx∫ x/cos^2 dx
F´ = 1/(COS ^2) X g= x
F= tan x g´= 1
∫ 1/(sen ^2) x dx= x tan x -∫ tan x dx=x tan + (sen x)/cosx
X tan + In (cos x) + c - 5∫ In (x) dxF´= 1 g= x
F= sen x g´= 1 /x
∫ x 1 /x= x/1 . 1 /x- ∫ x In x
x In (x) +c - 6∫ x^2 In x dxF´= x^2 g=In x dx
F= In x g´= 1 /x dx
=x^3/3 In x dx - ∫ x^3 ∫ 1 /x
=x^3/3 In x dx -1/3 ∫ x^3/3 dx
=x^3/3 In x dx - 1/3 ∫ x^2 dx
=In x dx (1/3) ( x^3/3) - 7∫ x^2 cos x dxF´= cos x g=x
F= sen x g´=1
2 ∫ x cos x= x sen- x -sen x dx
x sen x -cos x + c
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- Flashcards on Untitled, created by karina zuñiga on 21/09/2018.
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- karina zuñiga
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