Mind map
The Wave Equation
Map content
The Wave Equation
Initial Value Problem
- δy/δt at t=0
- p(x)
- y(x,t) at t=0
- h(x)
- y(x,t) = ½h(x-ct) + ½h(x+ct) +1/2c∫p(s)ds integral from (x-ct) to (x+ct)
- δy/δt at t=0
Harmonic Solutions
- y(x,t) = A(x)cos(ωt)
- A(x) = A₁cos(ωx/c) + A₂sin(ωx/c)
- y(x,t) = A(x)cos(ωt)
D'Alembert's Solution
- y(x,t) = f(x-ct) + g(x+ct)
δ²y/δt² = c² δ²y/δx²
- c² = T/ρ
- 2nd order, linear
Group and Phase Velocity
- Cph = ω(k)/k
- [graph wave]
- y(x,t) = A₀ exp[iθ]; θ = ωt-kx
- [graph wave packets]
Complex Solution
- y(x,t) = A₀ exp[i(ωt-kx)]
- ω² = c²k²
- τ = 2π/ω
- λ = 2π/k
- λ = cτ
Two K Solutions
- Produces wave packets
- y(x,t) = a cos(ω₁t-k₁x) + a cos(ω₂t-k₂x) = {2a cos[t(ω₂-ω₁)/2 - x(k₂-k₁)/2]} *cos[t(ω₂+ω₁)/2 - x(k₂+k₁)/2]
- [graph sweet]
- Rapidly varying signal
- Frequency: (ω₂+ω₁)/2
- Wavenumber: (k₂+k₁)/2
- Point of constant phase have speed: δx/δt = (ω₂+ω₁)/(k₂+k₁) ≈ ω₁/k₁ = Cph (if ω₂≈ω₁ and k₂≈k₁)
- Amplitude envelope
- Speed: (ω₂-ω₁)/(k₂-k₁) ≈ δω/δk|k₁ = Cg
- Rapidly varying signal
Fourier Solutions
Wave Reflection
Information
- Description
- Mind Map on The Wave Equation, created by hew5 on 18/11/2014.
- Created by
- hew5
- Views
- 17
- Rating