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SAME DENOMINATOR
1 + 3 = 1+3
8 8 8
= 4
8
= 1
2
DIFFERENT DENOMINATORS
1 + 3 = crosss multiply
7 2
= 1 x 2 + 3 x 2
7 x 2
= 2 + 21
14
= 23
14
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- Note on Untitled, created by Andrew Sherry on 02/01/2015.
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- Andrew Sherry
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