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Questions in this quiz (20)
1Y=5 HALLAR F´(X)
dy/dx=0- A5x
- B10
- C0
2 y= 5x^3 hallar f'(x)
dy/dx=〖5(3)x〗^(3-1)- A5x^2
- B5x^4
- C15x^2
3〖10x〗^(-7) + 8x HALLAR EN f'(x)
- A60x^6 + 8x^2
- B70x^6 + 8x
- C70x
4y=1/8 x^2 + 6/5 x^7 + 3/7 x^3 + 10x HALLAR f'(x)
- A1/4 x + 42/5 x^6 + x^7 + 10x
- B3/8 x + 36/6 x^6 + 2x^3 + 10x
- C3/6 x+4/5 x^7+3x
5Y= 11x^3 + 4/8 x^8 + 3x + 11 HALLAR f'(x)
- A33x+8x^7
- B33x^2 + 4x^7 + 3
- C33x^2 + 8x^9 + 11
6y= 4x^(1/3) + 9/6 x^(6/5) + 10x^6 HALLAR f'(x)
- A3/5 x + 9/5 + 54x^5
- B〖9/3 x〗^(-2/3) + 9/5 x^(1/5) + 60x^5
- C〖4/3 x〗^(-2/3) + 9/5 x^(1/5) + 34x^3
7y= 1/√x HALLAR f'(x)
- A(-1)/(2√(x^3 ))
- B1/√(x^3 )
- C3/√x
8y= 4/√x HALLAR f'(x)
- A(-2)/√(x^3 )
- B4/x^2
- C4/x
9y= 6/√(x^2+3x) HALLAR f'(x)
- A(3(2x+3))/√(〖(x)〗^2 )
- B((2x+3))/√(x^2 )
- C(3(2x+3))/(√(x^2+3x)^3 )
10Y= 3/√x HALLAR f'(x)
- A(-3)/√(x^3 )
- B(-3)/x
- C(-3)/(2√(x^7 ))
11y= (3x-4x)^5 HALLAR f'(x)
- A15(3x-4x)^4
- B(3x-4x)^4
- C15(3x)^4
12y= (2-4x)^3 HALLAR f'(x)
- A-12(2-4x) 2
- B12(2)
- C12(-4)
13y= (8x+5)^10 HALLAR f'(x)
- A80(8x)
- B80(8x+5)^9
- C80(8x+5)
14 y= s(t) t^5/6 - t^4/5 + t^3/4 - t^2/7 + 2/3 HALLAR f'(x)
- At^3/4 - t^2/12 + 2/3
- Bt^4/6 + t^3/5 + t^2/4 - t/7
- Ct^3/6 - t^4/7 + t/3
15 y= x^2/a HALLAR f’(x)
- Ax/a
- B4x^2/a
- C4/a
16 y= (s√t)/s HALLAR f'(x)
- A1/s(7)√(t^2 )
- B(3 √t)/5
- C(5√t)/3
17y= (2-x)/(1+3x^2 ) HALLAR f'(x)
- A(3x^2-21x+1)/(1+3x^2 )^2
- B(8x^2-21x)/(1+3x^2 )^^2
- C(3x^2-12x-1)/(1+3x^2
18y=(2-3x)/(4+5x) HALLAR f'(x)
- A(-18)/(4+5x)^2
- B10/(4+5x)^3
- C(-22)/(4+5x)^2
19y= x^(1/4) HALLAR f'(x)
- A2/√(x^3 )
- B1/(4√(x^7 ))
- C3/√(x^2 )
20y= x^(-1/4) HALLAR f'(x)
- A1/(2√(x^2 ))
- B1/(x√(1/2))
- Cx^3
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- Quiz on ESPAÑOL, created by Gabriel Xotlanihua on 04/06/2017.
- Author
- Gabriel Xotlanihua
- Language
- Español
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