Equilibrium Part II - Summary

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Summary of unit work up until 24/09/17
Chloe Drewery
Note by Chloe Drewery, updated more than 1 year ago
Chloe Drewery
Created by Chloe Drewery over 6 years ago
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What is an equilibrium? An equilibrium system is where the rate of the forwards reaction equals the rate of the reverse. This can only occur in a closed system with a reversible reaction. An equilibrium system can be disturbed by changing concentration, pressure or adding a catalyst; this disables equilibrium. Also at equilibrium the amounts of products and reactants stay the same. Another name for this is dynamic equilibrium "the rate of the forwards reaction is equal to the reverse".  Homogenous vs Heterogenous A homogenous reaction is where all the reactants and products (species) are in the same state.  Whereas if the mixture is heterogeneous, only gases and aqueous solutions go into the Kc expression; liquids and solids are left out. In a heterogenous reaction, the species are in different states.  Le Chatelier's Principle If there is a change in concentration, pressure or temperature the equilibrium will move to help counteract the change.  If equilibrium shifts to the right K increases. If equilibrium shifts to the left K decreases.  Temperature  Temperature is a condition meaning it affects the value of Kc. If you raise the temperature, equilibrium favours the endothermic direction. Therefore, if the reaction is exothermic in the forwards reaction, equilibrium will shift left and the value of Kc will decrease. Where as, if the reaction is endothermic in the forwards direction, equilibrium will shift to the right and K will increase. Catalyst A catalyst has no effect on the position of the equilibrium or the value of Kc. It doesn't increase yield but it means equilibrium will be reached quicker.  Concentration  Kc will stay the same. However, in order for the value of the expression to equal the value of Kc, the other concentrations will need to change.  Pressure Increasing the pressure shifts the equilibrium to the side with the fewest moles of gas. K stays the same no matter what you do to the pressure. For example - the haber process: Here there are more moles of gas on the left handside of the equation. N2 + 3H2 <=> 2NH3. Therefore by increasing the number of moles the value of the expression will decrease as the denominator is larger as the reactants will increase more. To restore, equilibrium must shift to the right, increasing the value of NH3 and decreasing the value of N2 and 3H2. However, decreasing the pressure means that the value of N2 3H2 is smaller, therefore the value of the expression is greater than Kc. To resolve this, equilibrium shifts to the left so the value of the reactants increases and the value of the products decreases to restore equilibrium. 

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