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Motion in 2-D

Sally Lancaster 9 questions Updated 6 May 2016

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Questions in this quiz (9)

  1. 1Resultant Velocity:
    1. Draw a diagram with the [blank_start]vertical component[blank_end] Vv and the [blank_start]horizontal component[blank_end] Vh and the [blank_start]resultant velocity[blank_end] V with the [blank_start]angle[blank_end] to the horizontal.
    2. Use [blank_start]Pythagoras[blank_end] and/or [blank_start]trigonometry[blank_end] to work out the resultant velocity/ Vv / Vh / the angle to the horizontal.
    Image for question 1
    1. Avertical component
    2. Bhorizontal component
    3. Cresultant velocity
    4. Dangle
    5. EPythagoras
    6. Ftrigonometry
  2. 2River Crossing:
    1. Arrange the information into a [blank_start]vector triangle[blank_end] and label the [blank_start]resultant[blank_end] velocity.
    2. Use trigonometry/Pythagoras for [blank_start]right-angled[blank_end] triangles to work out the [blank_start]resultant velocity[blank_end] and/or the [blank_start]angle[blank_end] to the horizontal/riverbank
    OR draw a [blank_start]scaled[blank_end] vector diagram to find angles and velocities with [blank_start]non-right-angled[blank_end] triangles.
    Image for question 2
    1. Avector triangle
    2. Bresultant
    3. Cright-angled
    4. Dresultant velocity
    5. Eangle
    6. Fscaled
    7. Gnon-right-angled
  3. 3What are the velocities relative to?Image for question 3
    1. Arelative to the ground
    2. Brelative to the water
    3. Crelative to the ground
    4. Drelative to the water
    5. Erelative to the ground
    6. Frelative to the water
    7. Grelative to the riverbank
    8. Hrelative to the riverbank
    9. Irelative to the riverbank
  4. 4Motion in 2-D:
    Horizontal motion and vertical motion are [blank_start]independent[blank_end] of each other.
    - Horizontal motion remains [blank_start]constant[blank_end] because it is [blank_start]unaffected[blank_end] by [blank_start]gravity[blank_end] so acceleration is [blank_start]zero[blank_end].
    - Vertical motion is affected by [blank_start]gravity[blank_end] so acceleration is always [blank_start]9.81[blank_end] ms^-2 [blank_start]downwards[blank_end] (on Earth).
    - This results in a [blank_start]parabolic[blank_end] shape as shown.
    Image for question 4
    1. Aindependent
    2. Bconstant
    3. Cunaffected
    4. Dgravity
    5. Ezero
    6. Fgravity
    7. G9.81
    8. Hdownwards
    9. Iparabolic
  5. 5Initially vertical velocity is [blank_start]upwards[blank_end] (taken as positive).
    Once it reaches [blank_start]its peak[blank_end] it changes to [blank_start]downwards[blank_end] (taken as negative).
    Therefore, because the [blank_start]sign[blank_end] of the velocity changes halfway through the motion, [blank_start]suvat[blank_end] can only be used for [blank_start]half[blank_end] of the motion.
    Image for question 5
    1. Aupwards
    2. Bdownwards
    3. Cdownwards
    4. Dupwards
    5. Eits peak
    6. Fthe ground
    7. Gsign
    8. Hmagnitude
    9. Isuvat
    10. Jvelocity
    11. Khalf
    12. Lall
  6. 6Air Resistance:
    - When air resistance acts on an object it causes [blank_start]deceleration[blank_end] horizontally as well as [blank_start]vertically[blank_end].
    - Deceleration due to air resistance results in a [blank_start]shorter[blank_end] distance covered [blank_start]horizontally[blank_end] and a lower [blank_start]maximum[blank_end] [blank_start]vertical[blank_end] [blank_start]height[blank_end] reached.
    - At maximum height, if horizontal deceleration has led to [blank_start]zero[blank_end] speed horizontally then the object will [blank_start]fall[blank_end] vertically
    ([blank_start]accelerate[blank_end] downwards due to [blank_start]gravity[blank_end]).
    Image for question 6
    1. Adeceleration
    2. Bvertically
    3. Cshorter
    4. Dhorizontally
    5. Emaximum
    6. Fvertical
    7. Gheight
    8. Hzero
    9. Ifall
    10. Jaccelerate
    11. Kgravity
  7. 7Projectiles on other Planets:
    - A lack of an atmosphere means almost no [blank_start]horizontal[blank_end] [blank_start]deceleration[blank_end] due to [blank_start]friction[blank_end] so it increases the [blank_start]range[blank_end] of the projectile.
    - A lower gravitational field strength would mean a [blank_start]lower[blank_end] vertical [blank_start]acceleration[blank_end] and therefore an [blank_start]increased[blank_end] time of flight (t = (v-u) / a) hence also increasing the [blank_start]range[blank_end] of the projectile.
    Image for question 7
    1. Ahorizontal
    2. Bvertical
    3. Cdeceleration
    4. Dacceleration
    5. Efriction
    6. Fair resistance
    7. Grange
    8. Htime of flight
    9. Ilower
    10. Jhigher
    11. Kacceleration
    12. Ldeceleration
    13. Mincreased
    14. Ndecreased
    15. Orange
    16. Pheight
  8. 8Projectile Calculations for a Full Flight:
    1. When finding time, t, remember to [blank_start]double[blank_end] the value you calculate to get the time for the [blank_start]full[blank_end] flight ([blank_start]suvat[blank_end] only works for [blank_start]half[blank_end] a flight).
    2. Use v = [blank_start]s / t[blank_end] for [blank_start]horizontal[blank_end] flight as usual.
    3. If asked to calculate an [blank_start]extra[blank_end] horizontal distance, use suvat to find the extra [blank_start]time[blank_end] and then s = [blank_start]v x t[blank_end] to find the extra [blank_start]distance[blank_end] (where v is the horizontal [blank_start]velocity[blank_end]).
    Image for question 8
    1. Adouble
    2. Bfull
    3. Chalf
    4. Dsuvat
    5. Es / t
    6. Fhorizontal
    7. Gextra
    8. Htime
    9. Iv x t
    10. Jdistance
    11. Kvelocity
  9. 9Projectile Calculations for Half a Flight:
    1. Just use [blank_start]suvat[blank_end] as normal for [blank_start]vertical[blank_end] motion.
    2. Use v = [blank_start]s / t[blank_end] for [blank_start]horizontal[blank_end] motion.
    Image for question 9
    1. Asuvat
    2. Bvertical
    3. Cs / t
    4. Dhorizontal

Information

Description
AS - Level Sally's Physics (Mechanics) Quiz on Motion in 2-D, created by Sally Lancaster on 04/03/2016.
Language
English
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History
Created on 4 Mar 2016 · updated on 6 May 2016
Tags
sally's physicsmechanicsas - level
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