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MATHS
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MATHS
NUMBERS
- FRACTIONS
- Adding/Subtracting-BOOM BOOM POW
- 1/4 + 7/10
- 4 X 7 = 28 and 1 x 10 = 10
- 4 x 10 = 40, so 28 + 10 = 38/40-19/20
- 4 X 7 = 28 and 1 x 10 = 10
- 1/4 + 7/10
- Multiplying
- Multiply numerators together
- Multiply denominators together
- Simplify if possible
- Multiply denominators together
- Multiply numerators together
- Dividing
- Multiply the reciprocal of the fracton and continue working out like you would with multiplying
- Recurring decimals to fractions
- Let x equal the number being converted
- x = 0.45454545...
- multiply by 10 then 100
- 10x =4.54545... and 100x =45.4545...
- Subtract x from 100x as they have the same 1st decimal
- 100x - x = 45= 99x
- divide both sides by 99 and simplify if possible
- x = 45/99 or 5/11
- Let x equal the number being converted
- Adding/Subtracting-BOOM BOOM POW
- INDICIES
- Laws of indicies
- a^b x a^c = a^b+c -Multiplying
- a^b/a^c = a^b-c -Dividing
- (a^b)^c -Power to power
- a^b/a^c = a^b-c -Dividing
- a^b x a^c = a^b+c -Multiplying
- Negative indicies
- a^-b = 1/a^b
- a^0 = 1
- Fractional indicies
- The power of 1/2 means the square root
- 25^1/2 = 5
- A power of a fraction like 2/3 means 1st root the number, 2nd square it
- 27^2/3 = 9
- Cube root 27 = 3
- 3^2 = 9
- Cube root 27 = 3
- 27^2/3 = 9
- The power of 1/2 means the square root
- Laws of indicies
- STANDARD FORM
- 134000 = 1.34 x 10^5
- 0.000765 = 7.65 x 10^-5
- PERCENTAGES
- Percentage change
- change/original x 100
- Eg- car bought for £4000 then sold for £3500, calc % decrease
- 500/4000 x 100
- 0.125 x 100
- 12.5%
- 0.125 x 100
- 500/4000 x 100
- Eg- car bought for £4000 then sold for £3500, calc % decrease
- change/original x 100
- Reverse percentages
- Divide by % then x by 100
- Car sold for £7650, 15% less than what he bought it as, what was original price
- 100%-15% = 85%
- 85% = £7650
- /85
- 1% = £90
- x 100
- 100% = £9000
- 85% = £7650
- 100%-15% = 85%
- Car sold for £7650, 15% less than what he bought it as, what was original price
- Divide by % then x by 100
- Compound interest
- Initial x multiplier^time
- 8000 x 1.05^3 = £9261
- Multiplier for a 5% increase
- Initial amount invested
- Money invested for 3 years
- 8000 x 1.05^3 = £9261
- Initial x multiplier^time
- Percentage change
- DIRECT AND INVERSE PROPORTION
- Direct
- C is directly proportional to D when C=200, D=2 find C when D=5
- Can be to the square/cube etc
- C ~ D
- C = K x D
- K= the constant of proportionality
- 200 = K x 2
- Substitute in C and D
- 200/2 = K = 100
- Work out K
- So to find C when D = 5 the formula is
- C = 100 x 5
- C = 500
- C = 100 x 5
- C = K x D
- C is directly proportional to D when C=200, D=2 find C when D=5
- Inverse
- P is inversely proportional to Q when P=10, Q=2 find P when Q=4
- Can be to square/cube etc
- P ~ 1/Q
- P = K/Q
- 10 = K/2
- Substitute in P and Q
- 10 x 2 = K = 20
- Work out K
- So to fine P when Q= 4 the formula is
- P=20/4
- P=5
- P=20/4
- 10 = K/2
- P = K/Q
- P is inversely proportional to Q when P=10, Q=2 find P when Q=4
- Direct
- FRACTIONS
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- Description
- GCSE Maths Mind Map on MATHS, created by Kati Hulme on 12/10/2017.
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- Kati Hulme
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