Physics GRE Prep - Classical Mechanics

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Chapter 1 Equations and Concepts from Conquering the Physics GRE
Hayden Tornabene
Flashcards by Hayden Tornabene, updated more than 1 year ago
Hayden Tornabene
Created by Hayden Tornabene almost 9 years ago
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Question Answer
Blocks on Ramps: Force Parallel and Force Perpendicular Fg,par=mgsinθ
Fg,perp=mgcosθ
Force of Friction (Normal Force) Ff=μmgcosθ
N=mgcosθ
Kinematic Equations x(t)=v0xt+x0
y(t)=12gt2+v0yt+y0
Only use kinematics if you need to know the explicit time dependence of a system. Energy considerations are faster otherwise.
Initial and Final Velocity Equation v2fv2i=2aΔx
Radial Acceleration for Uniform Circular Motion a=v2r
Centripetal Force for Uniform Circular Motion F=mv2r
Does not tell you what kind of force acting on body, just that a body moving in uniform circular motion has this force.
Types of Energy Translational Kinetic: 12mv2
Rotational Kinetic: 12Iω2
Gravitational Potential: mgh
Spring Potential: 12kx2
Potential Energy Line Integral ΔU=baFdl
For any conservative force - Integral is indirection of the force vector.
Gravitational Force and Gravitational Potential Fgrav=Gm1m2r2ˆr
U(r)=GmMr
Potential Energy and Force Relationship F=U
Linear Velocity of Rolling without Slipping v=Rω
Questions regarding which arrives with slower linear velocity are NOT questions of which arrive first. Need kinematics. Ex. energy expression for a sphere with mass m and radius r. mgh=12mv2+12(25mr2)ω2
REMEMBER: ω=vr
Work Energy Theorem - In terms of Kinetic Energy - In terms of Force Einitial+Wother=Efinal
W=ΔKE
W=Fdl
Linear Collisions Conservation of Momentum Two balls collide, M on m with M scattering at θ with initial velocity V with the final velocity equal for both at v. What is the scattering angle of ϕ of m? MV=Mvcosθ+mvcosϕ
(parallel to initial) 0=Mvsinθ+mvsinϕ
(perpendicular to initial) ϕ=sin1(Mmsinθ)
Using limiting cases, triaging is essential. Finding phi analytically takes time.
Angular momentum of a point particle and for an extended body. L=rxp
L=Iω
Torque (Angular Force) τ=rxF
Scalar Analogues of p=mv and F=dpdt Angular Momentum: L=Iω Torque: τ=dLdt The vector angular momentum L is generally parallel to ω with the angular momentum determined by the right hand rule.
Moment of Inertia (General and Extended Objects) I=mr2
I=r2dm
for dm = ρdV and ρ=Ar3 Compute the integral to find the constant A and then insert into the extended objects integral. Ex. ρ(x)=Ax2 M=L0ρ(x)dx=13AL3A=3ML3
Parallel Axis Theorem I=ICM+Mr2
For penny through center, I=12MR2 For penny axis through edge, I=12MR2+MR2
Center of Mass Displacement from Origin rCM=rdmM
Must solve three integrals, one for each dimension. Remember to select a volume integral and corresponding coordinate system that capitalizes on symmetry. For a system of point masses: rCM=ΣirimiM
Lagrangian Function Scalar Function L(q,˙q,t)=TU
for T kinetic energy, U potential energy, and q the generalized coordinate describing degrees of freedom.
How do you compute the correct expression for T in the Lagrangian? 1. Write down expressions for Cartesian coordinates in terms of chosen coordinates q. 2. Differentiate x,y,z to get ˙x,˙y,˙z 3. Form kinetic cartesian energy, T=12m(˙x2+˙y2+˙z2) for point particle, T=12Iω2 for an extended object. For extended object, must express ω in terms of ˙q, but this is easy as the two are generally equal. See page 20 in notebook for excellent example.
Euler-Lagrange Equations ddtδLδ˙q=δLδq
One equation for each degree of freedom, q. Remember that ddt is a total time derivative, not a partial derivative. I.e. ddtm˙x=m¨x
Momentum Conjugate to q (Lagrangian) δLδ˙q
Iff the Lagrangian is independent of a coordinate q, the corresponding conjugate momentum quantity, δLδ˙q, is conserved. Quantities whose time derivatives are zero are conserved quantities.
Hamiltonian H(p,q)=Σipi˙qiL
for pi=δLδ˙qi If the potential energy is not explicitly dependent on velocities of time, H = T + U Iff the Hamiltonian is independent of a coordinate 1, the corresponding conjugate momentum p is conserved.
Hamiltonian for Particle Moving in One Dimension H=T+U=p2x2m+U(x)
Hamiltonian for Particle Moving in 2D Polar H=p2r2m+p2θ2mr2
Hamilton's Equations Scalar function encoding equations of motion: ˙p=δHδq
˙q=δHδp
Lagrangian for a Simple Pendulum Take corresponding derivatives - e.g. ˙x=lcosθ˙θcosϕlsinθsinϕ˙ϕ
Plug the ˙x,˙y,˙z into the expression for T=12m(˙x2+˙y2+˙z2)
Simplify and put into L = T - U for U=mgz=mglcosθ
Conservation of Conjugate Momentum Example For the Lagrangian independent of ϕ, pϕ is conserved. Therefore the following quantity is conserved: pϕ=δLδ˙ϕ
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