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Notes

Volume And problem solving

Latoya mdg Math 8 English 1 page

Content of the notes (1)

Page 1

Volume of a prism

Volume of a cylinder

Solving problems involving prism and cylinders

Formula:

(Cylinder) - V = (π x r2) x h

Formula:

(Rectangular prism) - V = LxWxH

(Cube) - V = S3

(Right triangle) - V = (bxh ÷ 2) x h

Examples

(Prism)

Rectangular Prism

Volume And problem solving

(LxWxH)

10x4x5 = 200m

Cube

Volume And problem solving

(S3)

5x5x5 = 125cm

Right Triangle

Volume And problem solving

(bxh ÷ 2) x h

8x10 ÷ 2 x 20 = 800

Example

(π x r2) x h

π x 42 x 6 = 301.4

Volume And problem solving

Volume And problem solving

π x r2 x h

62.8 = π x 22 x h

π x 22 = 12.56 x h

62.8 ÷ 12.56 = 5

Volume And problem solving

Information

Description
8 Math (Grade 8) Note on Volume And problem solving, created by Latoya mdg on 27/05/2015.
Created by
Latoya mdg · May 2015
Updated
Feb 19, 2016
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