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MO8 Carbonyl containing functional groups

Mer Scott 8 preguntas

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Preguntas del test (8)

  1. 1Intermolecular H bonds are not possible or aldehydes and ketones but they are still very soluble in protic solvents.
    1. AVerdadero
    2. BFalso
  2. 2Aldehydes and ketones can form hydrates (two -OH groups off one carbon that was a [blank_start]carbonyl[blank_end] carbon). The oxygen in water acts as the [blank_start]nucleophile[blank_end]. This occurs in an [blank_start]acid[blank_end] catalysed reaction. The more electron [blank_start]withrdawing[blank_end] the substituents of the carbonyl carbon are, the more hydrate is formed.
    1. Acarbonyl
    2. Bnucleophile
    3. Celectrophile
    4. Dacid
    5. Ebase
    6. Fwithrdawing
    7. Gdonating
  3. 3A lactam is a cyclic amide.
    1. AVerdadero
    2. BFalso
  4. 4Amides can hydrogen bond with other amides.
    1. AVerdadero
    2. BFalso
  5. 5Amides are chemically stable because:
    1. AThey are resonance stabilized.
    2. BThey have no reactive lone pair of electrons.
    3. CThe oxygen is very electron withdrawing.
  6. 6Lactones and carbamates are classified as esters.
    1. AVerdadero
    2. BFalso
  7. 7Esters are [blank_start]polar[blank_end], and [blank_start]cannot[blank_end] form intermolecular H bonds. They are however still [blank_start]very soluble[blank_end] in protic solvents due to their H bonding.
    1. Apolar
    2. Bnon-polar
    3. Ccannot
    4. Dcan
    5. Every soluble
    6. Fvery insoluble
  8. 8Phosphate esters make drugs very soluble, which is useful for formulating drugs meant to be injected intravenously.
    1. AVerdadero
    2. BFalso

Información

Descripción
(Molecules) PHCY211 Test sobre MO8 Carbonyl containing functional groups, creado por Mer Scott el 08/04/2018.
Idioma
English
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