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Pythagorean Theorem Quiz

Selam H

Basic Derivative Rules

Description

Basic Derivative Rules

Flashcards by Bill Andersen, updated more than 1 year ago

	Created by Bill Andersen almost 10 years ago

270

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(4)

Resource summary

Question	Answer
Derivatives	Derivatives
Basic Rules	Basic Rules
Constant Rule $f(x)=k$	$f'(x)=0$
Constant Multiple Rule $f(x)=kx$	$f'(x)=k$
Power Rule $f(x)= x^\mathrm{n}$	$f'(x)= \mathrm{n}\cdot x^\mathrm{n-1}$
Sum/Difference rule $y= f(x) + g(x)$	$y'= f'(x) + g'(x)$
Product Rule $y = f(x)g(x)$	$y' = f(x)g'(x)+g(x)f'(x)$
Quotient Rule $y = \frac {f(x)} {g(x)}$	$y' = \frac {g(x)f'(x)-f(x)g'(x)} {\left( g(x) \right) ^2}$
Trig derivatives	Trig derivatives
$f(x)=\sin x$	$f'(x)=\cos x$
$f(x)=\cos x$	$f'(x)=-\sin x$
$f(x)=\tan x$	$f'(x)=\sec^2 x$
$f(x)=\sec x$	$f'(x)=\sec x \cdot \tan x$
$f(x)=\csc x$	$f'(x)= - \csc x \cdot \cot x$
$f(x)=\cot x$	$f'(x)= - \csc^2 x$
$f(x)= \sin^{-1}x$	$f'(x)=\frac{1}{\sqrt{1-x^2}}$
$f(x)= \cos^{-1}x$	$f'(x)=\frac{-1}{\sqrt{1-x^2}}$
$f(x)=tan^{-1}x$	$f'(x)=\frac{1}{1+x^2}$
$f(x)=cot^{-1}x$	$f'(x)=\frac{-1}{1+x^2}$

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1 comment

Aureliano Cardoso

almost 5 years ago

That's amazing!!! thanks!!!

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