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Flowchart

Choosing and how to do a statistical test

Benjamin Smith Psychology AS level English

Flowchart content

  1. What level of measurement is the data?

  2. Collected Data

  3. Nominal

  4. Is the data a test of association/correlation or a test of difference and if so are they related

  5. Create an aim and hypothesis and conduct an experiment

  6. Unrelated Design

  7. Chi-squared

  8. Related Design

  9. Sign test

  10. Correlation / Association

  11. Chi-squared

  12. Ordinal

  13. Is the data a test of association/correlation or a test of difference and if so are they related

  14. Unrelated Design

  15. Mann-Whitney

  16. Related Design

  17. Wilcoxon

  18. Correlation / Association

  19. Spearman's rho

  20. Interval

  21. Is the data a test of association/correlation or a test of difference and if so are they related

  22. Unrelated Design

  23. Unrelated t-test

  24. Related Design

  25. Related t-test

  26. Correlation / Association

  27. Pearson's r

  28. Step 1

    Rank the rating considering both groups and rating them together. Lowest number has a rank of 1. If you have more than 1 of the same number use the mean of the ranks so 8 and 9 will be 8.5

  29. Step 2

    Work out the value of U using one of:

    - UA = RA - [NA(NA + 1]

    - UB = RB - [NB(NB + 1)]

    or

    - Ua = nanb + {na(na+1)}/{2} - E`Ra

    - Ub = nanb + {nb(nb+1)}/{2} - E`Ra

  30. Step 3:

    Work out the critical value and if the results were significant, the calculated value has to be less than or equal to the critical value

  31. Step 1

    Calculate a difference and rank the difference. When ranking ignore the signs. If the difference is zero the data is not included in the ranking

  32. Step 2

    Working out the value of T. T is the calculated value which is the sum of the less frequent sign

  33. Step 3

    Find the crtical value and work out if the results are significant. To by significant the calculated T value must br less than or equal to the critical value

  34. Step 1

    Rank each set of scores separately in each condition from lowest to highesst. If there are two of the same score take the mean of the ranks

  35. Step 2

    Find the difference between each pair of ranks and square the difference. Add up the difference of the ranks

  36. Step 3

    Work out the value of rho using:

    rho = {6E`d^2}/{N(N^{2} -1}

  37. Step 4

    Find out the critical value and see if the results are significant. To be significant the calculated value (correlation value) must be equal to or more than the critical value

  38. Step 1

    Calculate the sum of the scores for x and y

  39. Step 2

    Square each x and value and add up the values

  40. Step 3

    Multiply x and y for each participant and add up these values

  41. Step 4

    Work out the value of r using:

    r = {N(E`xy) - (E`x)(E`y)}/{¬{[NE`x^{2} - (E¬x)^{2}][NE`y^{2} - (E`y)^{2}}

  42. Step 5

    Calculate the df value by doing N - 2 and finding the critical value. For the results to be significant the calculated value (r) must be bigger than or equal to the critical value

  43. Step 1

    Calculate the sum of the scores for group A and B

  44. Step 2

    Square each x and value and add up the values

  45. Step 3

    Work out the values for Sa = {E`Xa^{2} - (E`Xa)^{2}}/{Na}

    Sb = {E`Xb^{2} - (E`Xa)^{2}}/{Nb}

  46. Step 4

    Work out the value of t by doing:

    t = {X`a - X`b}/{ ¬{({Sa + Sb}/{Na + Nb - 2})({Na + Nb}/{NaNb})} }

  47. Step 5

    Work out the value of df by doing Na + Nb - 2. Find the critical value and see if the results are significant. To be significant the calculated value of t must be equal to or more than the critical value

  48. Step 1

    Calculate the difference (d) between scores for condition A and condition B. Then add up the values

  49. Step 2

    Square each difference and add up the values

  50. Step 3

    Work out the value of t by doing:

    t = ¬{{E`d^{2} - {E`d)^{2}}/{N}}/{N(N - 1)}

  51. Step 3

    Work out the value of df by doing N - 1 and find out the critical value. To be significant the calculated value must be equal to or more than the critical value.

  52. Step 1

    Draw out a a contingency table

  53. Step 2

    Calculate the expected frequencies fro all of the cells. An expected value if the value expected if there was no difference between the two groups

  54. Step 3

    Work out the value of E - O for each cell

  55. Step 4

    Square the value for E -O and then divid the value by E. This is the X^2 value (chi-squared value)

  56. Step 5

    Calculate the df value by doing (rows - 1) * (columns -1). Find out the critical value and work out if the results are significant. The value if significant if the X^2 value (calculated value) must be equal to or more than the critical value

  57. Step 1

    Draw out a a contingency table

  58. Step 2

    Calculate the expected frequencies fro all of the cells. An expected value if the value expected if there was no difference between the two groups

  59. Step 3

    Work out the value of E - O for each cell

  60. Step 4

    Square the value for E -O and then divid the value by E. This is the X^2 value (chi-squared value)

  61. Step 5

    Calculate the df value by doing (rows - 1) * (columns -1). Find out the critical value and work out if the results are significant. The value if significant if the X^2 value (calculated value) must be equal to or more than the critical value

  62. Step 1

    Subtact the one score from the other but only record the sign so if the answer is negative recod a - sign or if it is positive recod a + sign. If the answer is 0 record a = sign

  63. Step 2

    Add up all the positive and negative sign

  64. Step 3

    Take the less frequent sign, this is the calculated value.

  65. Step 4

    Find out the critical value and find out if the results are significant. To be significant the calculated value must be equal to or less than the critical value

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AS level Psychology Flowchart on Choosing and how to do a statistical test, created by Benjamin Smith on 29/04/2018.
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Benjamin Smith
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