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Chemistry Unit 1
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Chemistry Unit 1
Mass Number = Number of Protons + Neutrons (in the nucleus/atom)
Relative Atomic Mass = The mean mass of an atom of an element compared to one twelfth the mass of a 12C atom.
The first ionisation energy is the enthalpy change when one mole of gaseous atoms forms one mole of gaseous ions with a single positive charge
- The second ionisation energy is the enthalpy change when one mole of gaseous ions with a single positive charge forms one mole of gaseous ions with a double positive charge
- Ti+ (g) --> Ti2+ (g) + e-
- X(g) --> X+ (g) + e-
- 1.The attraction of the nucleus (The more protons in the nucleus the greater the attraction)
- 2. The distance of the electrons from the nucleus (The bigger the atom the further the outer electrons are from the nucleus and the weaker the attraction to the nucleus)
- 3. Shielding of the attraction of the nucleus (An electron in an outer shell is repelled by electrons in complete inner shells, weakening the attraction of the nucleus)
- The second ionisation energy is the enthalpy change when one mole of gaseous ions with a single positive charge forms one mole of gaseous ions with a double positive charge
Emperical Formula: the simplest whole number ratio of atoms of each element in a compound
Covalent Bond: a shared pair of electrons
Dative Covalent Bond: A covalent bond in which the shared pair of electrons are provided by just one of the bonded atoms
Electronegativity: The power of an atom to withdraw electron density from a covalent bond
Structural Isomerism: Compounds which have the same molecular formula but a different structural formula/displayed formula
Cracking: A process used by the petroleum industry to produce shorter alkanes and alkenes from longer alkanes
Ideal Gas Equation: pV=nRT
No. of moles = Mass/Mr
Concentration = No. of moles/Volume
Atom Economy = (mass desired product / mass all reactants)x100
% Yield = (Actual yield / Theoretical yield)x100
Mass Spectrometry:
- Step 1) Ionisation •Sample is dissolved in a polar solvent •A high voltage is applied to sample •The particles lose an electron ( or more) •Forming positive ions with different charges E.g. Ti Ti+ + e–
- Step 2) Acceleration •Positive ions are accelerated by an electric field •To a constant kinetic energy
- Step 3) Deflection •The positive ions with smaller m/z values will have the same kinetic energy as those with larger m/z and will move faster. •The heavier particles take longer to move through the drift area. •The ions are distinguished by different flight times
- Step 4) Detection •The ions reach the detector and generate a small current, which is fed to a computer for analysis. The current is produced by electrons transferring from the detector to the positive ions. The size of the current is proportional to the abundance of the species
- Step 3) Deflection •The positive ions with smaller m/z values will have the same kinetic energy as those with larger m/z and will move faster. •The heavier particles take longer to move through the drift area. •The ions are distinguished by different flight times
- Step 2) Acceleration •Positive ions are accelerated by an electric field •To a constant kinetic energy
- Step 1) Ionisation •Sample is dissolved in a polar solvent •A high voltage is applied to sample •The particles lose an electron ( or more) •Forming positive ions with different charges E.g. Ti Ti+ + e–
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- Chem 1 revision
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- farrukh riaz · Oct 2016
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- Oct 21, 2016
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- Created by Emily Wordsworth · Sep 14, 2015
- Copied by farrukh riaz · Oct 20, 2016
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